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LiRa [457]
2 years ago
11

Explain how your experimental data for Rf values are, or are not, consistent with your predictions of enantiomeric and diastereo

meric relationships between the menthol stereoisomers. What other data do you have for these compounds that support your predictions
Chemistry
2 answers:
algol132 years ago
5 0

Question is incomplete, complete question is as follows:

Explain how your experimental data for Rf values are, or are not, consistent with your predictions of enantiomeric and diastereomeric relationships between the menthol stereoisomers. What other data do you have for these compounds that support your predictions

Results from Lab:

Rf (+menthol) = .447

Rf (+isomenthol) = .395

Rf (+neomenthol)= .487

Rf (-menthol) = .434

Answer:

(+) menthol and (-) menthol are enantiomers  (because they both have almost same Rf values and vary a little i-e 0.447 for (+menthol) and 0.434 (for - menthol) hence declared as enantiomers)

(+) menthol and (+) neomenthol are diastereomers (As they have different Rf values )

(-) menthol and (+) isomenthol are also diastereomers (They also have different Rf values)

hichkok12 [17]2 years ago
3 0

Answer:

Answer is explained below.

Explanation:

As (+) menthol and (-) menthol are enantiomers whose physical properties are same except optical activity so we can expect they have similar Rf values.

Whereas diastereomers have different physical properties and different Rf values.

For example when the (+) menthol , (-) menthol, isomenthol and neomenthol undergo TLC (thin layer chromatography) the

Rf values of.(+menthol) = .447

Rf (+isomenthol) = .395

Rf (+neomenthol)= .487

Rf (-menthol) = .434

The above data shows that (+) menthol and (-) menthol have almost same Rf values and vary a little i.e 0.447 and 0.437. So we can conclude them as enantiomers

Whereas (+) menthol or (+) neomenthol or (+) isomenthol i.e 0.447 , 0.395 and 0.487 have different Rf values. We can conclude them as diasteromers.

(+) menthol and (-) menthol - enantiomers

(+) menthol and (+) neomenthol- diastereomers

(-) menthol and (+) isomenthol - diastereomers

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Nesterboy [21]

Answer:

P(total) = 1110 mmHg

Explanation:

According to the Dalton law of partial pressure,

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Given data:

Sample A = 740 mmHg

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Total pressure = ?

Solution:

<em>Sample A:</em>

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

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<em>Sample B:</em>

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

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<em>Sample C:</em>

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

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6 0
2 years ago
1. Calculate the molarity of a sugar solution if 4 liters of the solution contains 8 moles of sugar
klio [65]

Answer:

The molarity of a sugar solution is 2 M.

Explanation:

Molarity is a concentration measure that expresses the moles of solute per liter of solution. In this case it is calculated with the simple rule of three:

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<span>Displaced volume :

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Mass =  4.50 g

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2 years ago
Among these processes, which is the slowest chemical reaction?
user100 [1]
After some thinking I have come to the conclusion that the answer is C.
8 0
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You wish to make a buffer with pH 7.0. You combine 0.060 grams of acetic acid and 14.59 grams of sodium acetate and add water to
aleksandr82 [10.1K]

Answer:

The pH of the buffer is 7.0 and this pH is not useful to pH 7.0

Explanation:

The pH of a buffer is obtained by using H-H equation:

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<em>Where pH is the pH of the buffer</em>

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<em />

Replacing:

pH = 4.74 + log [0.1779mol] / [0.001mol]

<em>pH = 6.99 ≈ 7.0</em>

<em />

The pH of the buffer is 7.0

But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,

this pH is not useful to pH 7.0

<em />

7 0
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