Density of a substance is defined as the mass of the substance divided by the volume.
Density of the substance= 0.242 g cm⁻³
volume of the substance= 2.50 in³
As, 1 in³= 16.39 cm³
So, 2.50 in³= 16.39× 2.50 cm³=40.97 cm³
As ,
Mass=volume ×Density
Mass=40.97 × 0.242
Mass=9.916 g.
Answer:
C₂H₂O₃
Explanation:
The empirical formula of a compound is derived bu finding the whole ratios of the constituent elements.
In succinic acid, the ratios of carbon to hydrogen to oxygen is calculated as follows:
<u>% mass</u>
Carbon- 40.60
Hydrogen - 5.18
Oxygen - 54.22
<u>RAM</u>
Carbon -12
Oxygen - 15.994
Hydrogen -1.008
<u>No of moles elements in the compound</u>
Carbon = 40.60/12=3.3833
Oxygen = 54.22/15.994= 3.39
Hydrogen= 5.18/1.008 = 5.1389
Mole ratios of the individual elements we divide by the smallest value of the number of moles.
Carbon: Hydrogen : Oxygen
3.3833/3.3833:3.39/3.3833:5.1389/3.3833
=1:1:1.5
We can multiply the value by 2 to get the whole number ratio.
=2:2:3
The empirical formula will be:
C₂H₂O₃
Answer
its a potassium elements
Explanation:
K 2,8,8,1 period num 4
group 1A
or 1s1 ,2s2 2p6, 3s1
its a metal reacted rapidly with water to form a colorless basic solution of potassium hydroxide (KOH) and hydrogen gas (H2). The reaction continues even when the solution becomes basic. The resulting solution is basic because of the dissolved hydroxide. The reaction is exothermic.
<h2>Answer:</h2>
The mass of the system will remain the same if there is no conversion of mass to energy in the reaction.
<h3>Explanation:</h3>
- If the system is closed, then according to the law of mass conservation the mass of the reaction system will remain the same.
- <u><em>Law of conservation of the mass: In simple words, it is described as the mass of a closed system can never be changed, it may transfer from one form to another or change into energy.</em></u>
- But if the reaction involves energy transfer like heat or light production, in this case, the mass can be changed.
Answer: 
Explanation:

Here Mn undergoes oxidation by loss of electrons, thus act as anode. silver undergoes reduction by gain of electrons and thus act as cathode.

Where both
are standard reduction potentials.
![E^0_{[Mn^{2+}/Mn]}= -1.18V](https://tex.z-dn.net/?f=E%5E0_%7B%5BMn%5E%7B2%2B%7D%2FMn%5D%7D%3D%20-1.18V)
![E^0_{[Ag^{2+}/Ag]}=+0.80V](https://tex.z-dn.net/?f=E%5E0_%7B%5BAg%5E%7B2%2B%7D%2FAg%5D%7D%3D%2B0.80V)
![E^0=E^0_{[Ag^{+}/Ag]}- E^0_{[Mn^{2+}/Mn]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D-%20E%5E0_%7B%5BMn%5E%7B2%2B%7D%2FMn%5D%7D)

The standard emf of a cell is related to Gibbs free energy by following relation:

= gibbs free energy
n= no of electrons gained or lost = 2
F= faraday's constant
= standard emf = 1.98V

Thus the value of
is 