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avanturin [10]
2 years ago
8

a square boat made from iron has overall dimensions of 2.00 cm x 11.0 cm x 11.0 cm. it has a mass of 213 g. what is its density

242 g/cm3 0.880 g/cm3 51500 g/cm3 1.14 g/cm3
Chemistry
2 answers:
Rus_ich [418]2 years ago
5 0
Volume:

2.00 x 11.0 x 11.0 => 242 cm³

mass : 213 g

D = m / V

D = 213 / 242

D = 0.880 g/cm³

Answer B

hope this helps!
kondor19780726 [428]2 years ago
3 0

Answer: Density of the boat will be 0.880g/cm^3

Explanation: Density of a substance is calculated using the formula:

Density=\frac{Mass}{Volume}   .....(1)

Here, Dimensions of a boat is given, we can calculate the Volume using:

Volume = length × breadth × height

Dimensions are 2.00cm × 11.00cm × 11.00cm

Volume = 2cm × 11cm × 11cm = 242cm^3

Mass of the boat = 213 grams

Putting values in equation 1, we get

Density=\frac{213g}{242cm^3}=0.880g/cm^3

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Hydroxyapatite, Ca 10 ( PO 4 ) 6 ( OH ) 2 Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34 × 10 − 59 2.34×10−59 , and d
Margarita [4]

Answer:

1.315x10⁻³M = [Ca²⁺]

Explanation:

Based in the reaction:

Ca₁₀(PO₄)₆(OH)₂(s) ⇄ 10Ca²⁺(aq) + 6PO₄³⁻(aq) + 2OH⁻(aq)

Solubility product, ksp, is defined as:

ksp = [Ca²⁺]¹⁰ [PO₄³⁻]⁶ [OH⁻]²

From 1 mole of hydroxyapatite are produced  10 moles of Ca²⁺ and 6 moles of PO₄³⁻. That means moles of PO₄³⁻ are:

6/10 Ca²⁺ = PO₄³⁻

Replacing in ksp formula:

ksp = [Ca²⁺]¹⁰ [0.6Ca²⁺]⁶ [OH⁻]²

As [OH⁻] is 2.50x10⁻⁶M and ksp is 2.34x10⁻⁵⁹:

2.34x10⁻⁵⁹ =  [Ca²⁺]¹⁰ [0.6Ca²⁺]⁶ [2.50x10⁻⁶]²

3.744x10⁻⁴⁸ = 0.046656[Ca²⁺]¹⁶

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<em>1.315x10⁻³M = [Ca²⁺]</em>

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I hope it helps!

5 0
2 years ago
34.62 mL of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H2SO4 solution. What is the concentration of the original sulfu
Igoryamba

0.1045M is the concentration of the original sulfuric acid solution

Explanation:

Titration is done to know the volume or concentration of unknown electrolyte.

Data given:

volume of acid = 50 ml

molarity of acid =?

volume of base NaOH = 34.62 ml

molarity of the base = 0.1510

For titration the formula used is,

Macid x Vacid = Mbase  x V base

Putting the values in above equation:

M acid x 50 = 34.62 x 0.1510

Macid = \frac{5.22762}{50}

           = 0.1045 M is the molarity of sulphuric acid solution used in neutralization of 0.1510 M base solution.

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2 years ago
Recalling that a beaker of water is two dimensional, what is the three dimensional shape of the micelle
saul85 [17]
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2 years ago
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Irina18 [472]

Answer:

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Explanation:

And so...

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8 0
2 years ago
Read 2 more answers
The pH of an aqueous solution is 4.32. What is the [OH–]?
Molodets [167]
2.10 x 10^-10 M. Ans


pH + pOH = 14
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= 9.68
Now, the concentration of [H+] is 10-7 M, then pH is 7 and for [OH-] = 10-7 M, the pOH is also 7.

Now, pOH = -log[OH-]
[OH-] = 10^- pOH
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8 0
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