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julia-pushkina [17]
2 years ago
12

Which number is equal to –906,060?

Chemistry
1 answer:
mamaluj [8]2 years ago
7 0
In absolute value it is equal to 906,060
In scientific notation it is equal to -9.06,060^5
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Write the word equation for the reaction of barium nitride with potassium
Irina18 [472]

Answer:

Well this is a metathesis or partner exchange reaction....and barium sulfate is as soluble as a brick...

Explanation:

And so...

Ba(NO3)2(aq)+K2SO4(aq)→2KNO3(aq)+BaSO4(s)⏐↓

Note that you simply HAVE TO KNOW that barium sulfate is insoluble....as is lead sulfate, and as is (less so) calcium sulfate

Explanation:

8 0
2 years ago
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A bottle of concentrated aqueous sulfuric acid, labeled 98.0 wt% h2so4, has a concentration of 18.0 m. (a) how many milliliters
nadya68 [22]
<span>n this order, Ď=1.8gmL, cm=0.5, and mole fraction = 0.9 First, let's start with wt%, which is the symbol for weight percent. 98wt% means that for every 100g of solution, 98g represent sulphuric acid, H2SO4. We know that 1dm3=1L, so H2SO4's molarity is C=nV=18.0moles1.0L=18M In order to determine sulphuric acid solution's density, we need to find its mass; H2SO4's molar mass is 98.0gmol, so 18.0moles1Lâ‹…98.0g1mole=1764g1L Since we've determined that we have 1764g of H2SO4 in 1L, we'll use the wt% to determine the mass of the solution 98.0wt%=98g.H2SO4100.0g.solution=1764gmasssolution→ masssolution=1764gâ‹…100.0g98g=1800g Therefore, 1L of 98wt% H2SO4 solution will have a density of Ď=mV=1800g1.0â‹…103mL=1.8gmL H2SO4's molality, which is defined as the number of moles of solute divided by the mass in kg of the solvent; assuming the solvent is water, this will turn out to be cm=nH2SO4masssolvent=18moles(1800â’1764)â‹…10â’3kg=0.5m Since mole fraction is defined as the number of moles of one substance divided by the total number of moles in the solution, and knowing the water's molar mass is 18gmol, we could determine that 100g.solutionâ‹…98g100gâ‹…1mole98g=1 mole H2SO4 100g.solutionâ‹…(100â’98)g100gâ‹…1mole18g=0.11 moles H2O So, H2SO4's mole fraction is molefractionH2SO4=11+0.11=0.9</span>
5 0
2 years ago
Mgcl2 has a concentration of 0.054 M in the ocean. How many grams are present in 25ml of sea water ​
d1i1m1o1n [39]

Answer:

0.129g MgCl2

Explanation:

For this we need to understand the concept of molarity.

Molarity is number of moles of solute/litres of solution

M=n/L

Here we are given molarity of 0.054M and volume of 25ml. we just plug this in formula to find moles of MgCl2

0.054=x/(25/1000) (we divided 25 by 1000 to convert it to litres of solution)

x=0.00135 moles of MgCl2 (we are not done yet the question asks for grams so to convert to grams we multiply by molar mass of MgCl2.)

0.00135molesMgCl2 x 95.211g MgCl2/1molMgCl2

= 0.129g MgCl2

3 0
2 years ago
URGENT!! 50 Points Please Help!! Will mark brainliest!! Assignment due in 30 minutes.
dedylja [7]

a) The least number of decimal points is 0 so you should round the answer to 43.

b) The least number of significant figures is 2 so round to 7.3

c)The least number of decimal places is 1 so round to 225.7

d) The least number of significant figures is 3 so round to 92.0

e) The least number of significant figures is 3 so round to 32.4

f) The least number of decimal places is 0 so round to 104m^3

Basically, for addition and subtraction round to the least number of decimal places found in the factors, and for multiplication and division round to the least number of significant figures found in the factors.

4 0
2 years ago
Using the solubility curve, what is the effect of increased temperature on the solubility of KBr in 100 grams of water? The solu
galina1969 [7]
The graph is needed to answer this question.

Solubility may increase or decrease with temperature depending on the properties of the solute and the solvent.

It is quite common that the solubility of the ionic compounds, like KBr, in water increases with temperature.

Use your solubility curve for the KBr and you wiil see a line that starts at a solubility a little greater than 50 grams of the salt in 100 grams of water for temperaute 0°C and increase linearly until almost 100 grams of the salt in 100 grams of water at 100°C.

So, in this case you can affirm that the solubility of KBr increases with the temperature.

Answer: the second option: the solubility increases.
7 0
2 years ago
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