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Zigmanuir [339]
1 year ago
9

A 2.67 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL H 2 O . What will be the fi

nal volume reading on the graduated cylinder, in mL?
Chemistry
1 answer:
Margaret [11]1 year ago
4 0

Answer:

12.50 mL

Explanation:

From the question given above, the following data were obtained:

Mass of Zinc = 2.67 g

Density of Zinc = 7.14 g/mL

Volume of water = 12.13 mL

Final volume reading =?

Next, we shall determine the density of the piece of zinc. This can be obtained as follow:

Mass of Zinc = 2.67 g

Density of Zinc = 7.14 g/mL

Volume of Zinc =?

Density = mass / volume

7.14 = 2.67 / volume of Zinc

Cross multiply

7.14 × volume of Zinc = 2.67

Divide both side by 7.14

Volume of Zinc = 2.67 / 7.14

Volume of Zinc = 0.37 mL

Finally, we shall determine the final volume reading of the graduated cylinder. This can be obtained as follow:

Volume of water = 12.13 mL

Volume of Zinc = 0.37 mL

Final volume reading =?

Final volume reading = (Volume of water) + (Volume of Zinc)

Final volume reading = 12.13 + 0.37

Final volume reading = 12.50 mL

Thus, the final volume reading of the graduated cylinder is 12.50 mL

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In the adjoining figure, the circles with the + sign represent protons and the empty circles represent neutrons. Determine which
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Answer: option C. 2 and 3.

Explanation:

1) Isotopes are atoms of a same element with different number of neutrons. That means that the isotopes of a same element have the same number of protons, since the number of protons is what identify an element.

2) For example, all the atoms of oxygen have 8 protons. But isotope oxygen-16 has 8 neutrons, while oxygen-18 has 10 neutrons.

3) In the figure there are 3 different atoms:

i) atom # 1 has 5 protons and 7 neutrons

ii) atom # 2 has 6 protons and 7 neutrons

iii) atom # 3 has 6 protons and 8 neutrons.

4) Hence the atoms with the same number of protons and different number of neutrons are the #2 and the # 3. So, they are the isotopes of the same element.

4 0
2 years ago
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A substance is 89.2% carbon by mass. how much of the substance would be needed to recover 34.6 mol of pure carbon?
kari74 [83]
1 mole of carbon contains 12 g
Thus, 34.6 moles will contain; 34.6 × 12 = 415.2 g
If a substance contains 89.2 % carbon, 
then, (415.2/89.2) ×100 =  465.47 g of the substance will be required to yield 34.6 moles of carbon.
8 0
2 years ago
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The chemical reaction that causes chromium to corrode in air is given by 4Cr+3O2→2Cr2O3 in which at 298 K ΔH∘rxn = −2256 kJ ΔS∘r
MAVERICK [17]

Answer:

-2092 kJ

Explanation:

Let's consider the chemical reaction that causes chromium to corrode in air.

4 Cr + 3 O₂ → 2 Cr₂O₃

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ΔH° - T × ΔS°

where,

  • ΔH°: standard enthalpy of the reaction
  • T: absolute temperature
  • ΔS°: standard entropy of the reaction

ΔG° = -2256 kJ - 298 K × (-0.5491 kJ/K)

ΔG° = -2092 kJ

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2 years ago
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Explain why groups 14 and 15 are better representatives of mixed groups than groups 13 and 16
Brrunno [24]
<h3><u>Answer</u>;</h3>

Groups 14 and 15 each contain metals, nonmetals, and metalloids while Group 13 contains metals and a metalloid, and Group 16 contains metalloids and nonmetals.

<h3><u>Explanation;</u></h3>
  • Groups 13–16 of the periodic table contain one or more metalloids, in addition to metals, nonmetals, or both.
  • Unlike other groups of the periodic table, which contain elements in one class, groups 13–16 referred to as mixed groups contain elements in at least two different classes. In addition to metalloids, they also contain metals, nonmetals, or both.
  • <em><u>Group 14 also known as the carbon group contains carbon which is a non metal, silicon and germanium which are metalloids and tin and lead which are metals.</u></em>
  • <em><u>Group 15 also known as the Nitrogen group contains non metals such as oxygen, metalloid tellurium and a metal polonium.</u></em>
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2 years ago
Which part of experimental design is most important to a scientist when replicating an experiment? Having exactly the same data
yarga [219]

Answer:

The answer to your question is below:

Explanation:

Having exactly the same data as the previous experiment I think that having the same data as the previous experiment is extremely important but not the most important, for me is the second most important.

Using the same procedure and variables as the previous experiment For me, this is the most importan thing when a scientist is designing an experiment, because if he or she follow exactly the same procedure and variables, then the results will be very close.

Conducting an experiment similar to the previous experiment  This characteristic is important but not the most important.

Using the same laboratory that was used in the previous experiment It is not important the laboratory, if the procedure and variables are the same, your experiment must give the same results in whatever laboratory.

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