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Zigmanuir [339]
1 year ago
9

A 2.67 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL H 2 O . What will be the fi

nal volume reading on the graduated cylinder, in mL?
Chemistry
1 answer:
Margaret [11]1 year ago
4 0

Answer:

12.50 mL

Explanation:

From the question given above, the following data were obtained:

Mass of Zinc = 2.67 g

Density of Zinc = 7.14 g/mL

Volume of water = 12.13 mL

Final volume reading =?

Next, we shall determine the density of the piece of zinc. This can be obtained as follow:

Mass of Zinc = 2.67 g

Density of Zinc = 7.14 g/mL

Volume of Zinc =?

Density = mass / volume

7.14 = 2.67 / volume of Zinc

Cross multiply

7.14 × volume of Zinc = 2.67

Divide both side by 7.14

Volume of Zinc = 2.67 / 7.14

Volume of Zinc = 0.37 mL

Finally, we shall determine the final volume reading of the graduated cylinder. This can be obtained as follow:

Volume of water = 12.13 mL

Volume of Zinc = 0.37 mL

Final volume reading =?

Final volume reading = (Volume of water) + (Volume of Zinc)

Final volume reading = 12.13 + 0.37

Final volume reading = 12.50 mL

Thus, the final volume reading of the graduated cylinder is 12.50 mL

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During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
Brrunno [24]

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

3 0
1 year ago
(f) what is the observed rotation of 100 ml of a solution that contains 0.01 mole of d and 0.005 mole of l? (assume a 1-dm path
never [62]
<span>Answer: .01 moles of D to .005 moles of L ~ so, .01+.005 = .015 total; using this total value, divide the portions of D and L. so .01/.015 to .005/.015 ~ 67% D to 33% L. And thus, the enantiomer excess will be 34%.</span>
4 0
2 years ago
Read 2 more answers
Identify Earth’s neighbors in the solar system by choosing the correct answer. The are bodies of rock or gas that are named for
SpyIntel [72]

Answer: The are bodies of rock or gas that are named for ancient gods.

Explanation:

Earth is the THIRD planet in the solar system. It support life of all living organisms.

VENUS is the second planet in our solar system. It is named after the Roman goddess of love and beauty.

MARS is the fourth planet in our solar system. It is named after the Roman goddess of war.

Thus, Venus and Mars, are EARTH NEIGHBORS

6 0
2 years ago
Read 2 more answers
What is the change in enthalpy in kilojoules when 3.24 g of CH3OH is completely reacted according to the following reaction 2 CH
vodka [1.7K]

Answer:

12.78 kJ

Explanation:

The correct balanced reaction would be

2CH_3OH\rightarrow 2CH_4+O_2\Delta H=252.8\ \text{kJ}

Mass of methanol = 3.24\ \text{g}

Moles of methanol can be obtained by dividing the mass of methanol with its molar mass (32.04\ \text{g/mol})

\dfrac{3.24}{32.04}=0.10112\ \text{moles}

Enthalpy change for the number of moles is given by

\dfrac{\text{Number of moles of methanol in the reaction}}{\text{Enthalpy change in the reaction}}=\dfrac{\text{Number of moles in 3.24 g of methanol}}{\text{Enthaply in change in the mass of methanol}}

\\\Rightarrow\dfrac{2}{252.8}=\dfrac{0.10112}{\Delta H}\\\Rightarrow \Delta H=\dfrac{0.10112\times 252.8}{2}\\\Rightarrow \Delta H=12.781568\approx 12.78\ \text{kJ}

The change in enthalpy is 12.78 kJ.

5 0
2 years ago
The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.
ASHA 777 [7]
We assume that this gas is an ideal gas. We use the ideal gas equation to calculate the amount of the gas in moles. It is expressed as:

PV = nRT
(672) (1/760) (36.52) = n (0.08206) ( 68 +273.15)
n = 1.15 mol of gas

Hope this answers the question. Have a nice day.
7 0
1 year ago
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