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Alina [70]
1 year ago
12

A "shielding gas" mixture of argon and carbon dioxide is sometimes used in welding to improve the strength of the weld. if a gas

cylinder of this two-part mixture was at 4.0 atm pressure and this mixture was 90.% argon, what would be the pressure due to the carbon dioxide gas component?
Chemistry
2 answers:
kodGreya [7K]1 year ago
6 0
Dalton's Law of Partial Pressures, commonly applied to ideal gases, explains that the partial pressures of individual, non-reacting gases are equal to the total pressure exerted by the gas mixture. The given gas mixture composed of 90% argon and 10% carbon dioxide has the following partial pressures: 3.6 atm for argon and 0.4 atm for carbon dioxide (answer).
Radda [10]1 year ago
3 0

Answer is: the pressure due of carbon dioxide gas is 0.4 atm.

p(mixture) = 4.0 atm; mixture of argon and carbon dioxide gas.

ω(Ar) = 90% ÷ 100%.

ω(Ar) = 0.9; percentage of argon gas in mixture.

p(Ar) = 0.9 · 4.0 atm.

p(Ar) = 3.6 atm; pressure of argon gas.

The total pressure of an ideal gas mixture is the sum of the partial pressures of the gases in the mixture.

p(mixture) = p(Ar) + p(CO₂).

p(CO₂) = 4 atm - 3.6 atm.

p(CO₂) = 0.4 atm; pressure of carbon dioxide gas.

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Answer:

8.1×10^-8 mols-1

Explanation:

Now we have the mass of copper sulphate produced after three days. Recall that the rate of reaction is given as;

Rate= change in the concentration of product/time

At the beginning of the reaction, there was 0 moles of copper sulphate

After 72 hours or 259200 seconds, there was 3.4g/160gmol-1 = 0.021 moles of copper sulphate.

Note that 160gmol-1 is the molar mass of copper sulphate.

Hence;

Rate of reaction= 0.021 moles /259200 seconds

Hence, the rate of reaction is 8.1×10^-8 mols-1

Rate of reaction= 8.1×10^-8 mols-1

3 0
1 year ago
When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several
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<h3><u>Answer;</u></h3>

C) primary cell wall → plasma membrane → cytoplasm → vacuole

<h3><u>Explanation;</u></h3>
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1 year ago
What term refers to the coldest and densest zone, deep below the surface of a lake?
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1 year ago
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One crystalline form of silica (SiO2) has a cubic unit cell, and from X-ray diffraction data it is known that the cell edge leng
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Answer:

8 Silicon atom are present in unit cell.

16 oxygen atoms are present unit cell.

Explanation:

Number of atoms in unit cell = Z =?

Density of silica = tex]2.32 g/cm^3[/tex]

Edge length of cubic unit cell = a  = 0.700 nm = 0.700\times 10^{-7} cm

1 nm=10^{-7} cm

Molar mass of Silica  = 28.09 g/mol+16.00\times 2=60.09 g/mol

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

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M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

2.32 g/cm3=\frac{Z\times 60.09 g/mol}{6.022\times 10^{23} mol^{-1}\times (0.700\times 10^{-7}cm)^{3}}

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1 silicon is 2 oxygen atoms. then 8 silicon atoms will be 16 oxygen atoms.

5 0
2 years ago
Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m
dsp73

Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals. 

 

<span> </span>

7 0
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