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sashaice [31]
2 years ago
11

Propose a plausible mechanism for the reaction f2 + 2clo2 → 2fclo2 given that the rate law for the reaction is rate = k[f2][clo2

]. click in the answer box to activate the palette. do not include states of matter.
Chemistry
2 answers:
shepuryov [24]2 years ago
8 0

<u>The given reaction is:</u>

F2 + ClO2 → 2FClO2

Rate = k[F2][ClO2]

<u>Explanation:</u>

The possible mechanism for this reaction can be broken down into two steps with the slow step being the rate determining step

Step 1:       F2 + ClO2 → FClO2 + F ----------- Slow

Step 2:      F + ClO2 → FClO2           ----------- Fast

-----------------------------------------------------------

Overall:  F2 + 2ClO2 → 2FClO2

Rate = k[F2][ClO2]

 


ololo11 [35]2 years ago
5 0

Answer:

Step 1: slow dissociation of fluorine (controlling stage):

F_2+ClO_2-->FClO_2+F^-

Step 2: fast chlorine dioxide reaction with fluoride ions:

F^-+ClO_2-->FClO_2

Explanation:

Hello,

The undergoing chemical reaction:

F_2+2ClO_2-->2FClO_2

Could be attained via two steps forming the required plausible mechanism with the given reaction rate:

Step 1: slow dissociation of fluorine (controlling stage):

F_2+ClO_2-->FClO_2+F^-

Step 2: fast chlorine dioxide reaction with fluoride ions:

F^-+ClO_2-->FClO_2

In this case, it is necessary for the fluorine to be dissociated to promote the formation of the two FClO_2 molecules and its consequent simplification as the formed fluorine ions act as intermediates, thus, the overall reaction turn out into:

F_2+2ClO_2-->2FClO_2

Best regards.

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A sample of neon effuses from a container in 72 seconds. the same amount of an unknown noble gas requires 147 seconds. you may w
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The   second gas  is  identified  as  follows

by  Graham law  formula
let  the  unknown gas  be  represented  by  letter y

=time of  effusion of Neon/ time  of effusion of  y =   sqrt (molar mass of neon/molar  mass of y)

= 72  sec/ 147  sec =  sqrt( 20.18  g/mol/ y   g/mol)

square the  both  side  to  remove  the  square  root  sign

72^2/147^2  = 20.18 g/mol/y g/mol

=0.24 = 20.18g/mol/y g/mol

multiply  both side  by  y  g/mol
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6 0
2 years ago
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space capsules operate with an oxygen content of about 34%. assuming a total pressure of 780 mm Hg in the space capsule, what is
Lemur [1.5K]

265.2 mmHg is the partial pressure of oxygen in 780 mmHg of total pressure.

Explanation:

The partial pressure of a gas is defined as the individual pressure of the gas in total mixture. In an ideal gas all the constituent gases have partial pressure some of which will give total pressure of the gas.

The partial pressure of a gas is calculated by

total pressure x mole fraction of the gas.

Mole fraction of the oxygen present is 0.34 as it is 34% of the total gas.

\frac{34}{100} = 0.34  is the mole fraction

Total pressure is given as 780 mm Hg

The partial pressure can be calculated using the above formula:

Putting the values in equation:

780 x 0.34

= 265.2 mm Hg is the partial pressure of oxygen.

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2 years ago
When food spoils, it is a chemical reaction. For example, rancid butter is produced when the fat molecules in the butter undergo
Sergio039 [100]

Answer: Decreases the rate of reaction

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Does not decrease the rate of reaction

  • Store food in the open air.
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Explanation: Dehydration of food excludes water from food which is one of the factor needed by microorganisms for growth, <em>so it decreaese the rate of reaction.</em>

Transporting food in refrigerated trucks lowers the temperature of food and not many microorganisms are active at very low temperatures, so it <em>decreases the rate of reaction.</em>

Storing food in airtight containers excludes air which is one of the factors required for microbial activity, so <em>it decreases reaction rate.</em>

Storing food in refrigerators after opening also <em>lowers the temperature of food and hence the the rate of microbial activit</em>y.

Storing food in the open air <em>does not decrease microbial activity</em> instead it provides microorganisms with the favorable conditions for their activity such as air and water from water vapor in the air.

Placing food on a warm surface <em>does not decrease rate of reaction</em> because microorganisms are very active in warm and humid environments.

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2 years ago
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