There is an exact value for the standard volume at standard conditions of 1 atm and 273 K. This standard volume for any ideal gas is 22.4 L/mol. Thus,
Moles SO₂ = 5.9 L * 1 mol/22.4 L = 0.263 mol
The molar mass for SO₂ is 64.066 g/mol. So, the mass is:
Mass = 0.263 mol * 64.066 g/mol = <em>16.87 g SO₂</em>
Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2 cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius
Answer:
41.3 minutes
Explanation:
Since the reaction is a first order reaction, therefore, half life is independent of the initial concentration, or in this case, pressure.
So, fraction of original pressure = 
n here is number of half life
therefore, 
⇒ n= 3
it took 124 minutes to drop pressure to 1/8 of original value, half life = 124/3= 41.3 minutes.
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
Explanation:
It is given that lattice energy is -701 kJ/mol.
Whereas it is known that realtion between lattice energy and radius is as follows.
Lattice energy 
where, 
= +2, and 
= -2
Therefore, lattice energy of AB = 
= 
= -2804 kJ/mol
Thus, we can conclude that lattice energy of the salt ABAB is -2804 kJ/mol.
