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Mazyrski [523]
2 years ago
9

A compound contains 81.1 boron with the remainder being hydrogen what is the empirical formula of the compound

Chemistry
1 answer:
kari74 [83]2 years ago
4 0
Empirical formula is the simplest ratio of whole numbers of components making up the compound
Mass percentage of boron - 81.1 %
Mass percentage of hydrogen - 18.9 %
For 100 g of the compound
                                               B                        H
Mass                                   81.1 g                  18.9 g
Number of moles          81.1 g /11 g/mol       18.9 g/1 g/mol
                                          = 7.37 mol             = 18.9 mol
Divide by the least number of moles
                                           7.37/7.37 =1.00     18.9/7.37 =2.56
Since we get 2.56 that cannot be rounded off we have to multiply both boron and hydrogen values by 2
B = 1.00 x2 = 2.00
H = 2.56 x 2 = 5.12 rounded off to 5
Therefore empirical formula is
B₂H₅

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