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Fiesta28 [93]
1 year ago
15

a metal worker uses a cutting torch that operates by reacting acetylene gas, C2H2(g), with oxygen gas, O2(g), as shown in the un

balanced equation below: C2H2(g)=O2(g)= CO2(g) = H2O(g) = heat determine the mass of 25 moles of acetylene (gram-formula mass = 26 g/mol
Chemistry
2 answers:
harkovskaia [24]1 year ago
8 0

Answer:

650 grams

Explanation:

Given that acetylene gas reacts with oxygen to produce caobon dioxide, water and heat and the unbalnced equation is

C_2H_2(g)+O_2(g) \rightarrow CO_2(g) + H_2O(g)+ heat

Gram-formula mass of C_2H_2= 26 g/mol

So, mass of 1 mole of acelylene is 26 grams

Therefore, mass of 25 moles of acelylene=25x26=650 grams

Hence, the mass of 25 moles of acelylene is 650 grams

erastova [34]1 year ago
6 0

Answer:

650

Explanation:

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Answer:

Dust and smoke.

Explanation:

Dust and smoke are two different particles present in the air. Dust and smoke are different from one another due to their origin. Smoke formed from burning of materials while dust refers to the soil particles lifted by the wind due to their light weight. Dust and smoke are similar to each other due to their small in size, infinite number means uncountable and light weight.

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2 years ago
An ice cube is placed on a kitchen counter. Which best describes heat flow in this situation
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1 year ago
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In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)
Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}

{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L

{V_2}=0.27\ L

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0
2 years ago
A student needed exactly 45.3ml of a solution. what piece of glassware should that student use? justify your choice.
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The student should use the graduated cylinder. A graduated is the most common laboratory glassware when measuring volumes. It has calibrations by 1, 0.5 or 0.1 depending on the maximum volume. You have to make sure though, that you measure the volume by looking at the lower meniscus of the liquid at eye level.
7 0
1 year ago
A gas is initially at a pressure of 0.43 atm, and a volume of 11.7 liters. Then the pressure is raised to 3.61 atm and the volum
lukranit [14]

Answer:

D. 91.98K

Explanation:

The General Gas Law equation is given by,

\frac{P_1V_1}{T_1}  =  \frac{P_2V_2}{T_2}

From the question,

the initial pressure,

P_1 = 0.43 \: atm

the initial volume,

V_1 = 11.7 \: litres

the final temperature,

T_2=627K

the final pressure,

P_2=3.61atm

the final volume,

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Making

T_1

the subject of the expression, we obtain

T_1= \frac{P_1V_1T_2}{P_2V_2}

By substitution,

T_1= \frac{0.43 \times11.7 \times627}{3.61 \times9.5}

T_1=91.980K

Hence the initial temperature was 91.98 K

4 0
1 year ago
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