Answer:
650 grams
Explanation:
Given that acetylene gas reacts with oxygen to produce caobon dioxide, water and heat and the unbalnced equation is
Gram-formula mass of g/mol
So, mass of 1 mole of acelylene is 26 grams
Therefore, mass of 25 moles of acelylene=25x26=650 grams
Hence, the mass of 25 moles of acelylene is 650 grams
Answer:- 38.2 g.
Solution:- The equation used for solving this type of calorimetry problems is:
where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.
Water temperature is increasing from 14.5 degree C to 50.0 degree C.
= 35.5 degree C
q is given as 5680 J and specific heat value is .
The equation could be rearranged for m as:
Let's plug in the values in it:
m = 38.2 g
So, the mass of water in the kettle is 38.2 g.
Answer:
a)
b) 1657 €
Explanation:
Hola,
a) En este problema, vamos a considerar el millón de litros de agua anuales, ya que con ellos podemos calcular el calor requerido para dicho calentamiento, sabiendo que la densidad del agua es de 1 kg/L:
Luego, usamos la entalpía de combustión del metano para calcular su requerimiento en kilogramos, sabiendo que la energía ganada por el agua, es perdida por el metano:
b) En este caso, consideramos que a condiciones normales de 1 bar y 273 K, 1 metro cúbico de metano cuesta 0,45 €, con esto, calculamos las moles de metano a dichas condiciones:
Con ello, los kilogramos de metano que cuestan 0,45 €:
Luego, aplicamos la regla de tres:
0.715 kg ⇒ 0.45 €
2630 kg ⇒ X
X = (2630 kg x 0.45 €) / 0.715 kg
X = 1657 €
Regards.
Answer : The % of (+) limonene isomer = 79%
The % of (-) limonene isomer = 0%
The % of enantiomeric excess = 58%
Explanation : Enantiomeric excess (ee) is the measurement of purity used for chiral substances.
Given,
% of pure limonene enantiomer = The % of (+) limonene isomer = 79%
Therefore, The % of (-) limonene isomer = 0%
Formula used :
Where, ee → enantiomeric excess
Now, put all the values in above formula, we get the value of enantiomeric excess (ee).
= 58%