Answer: The reaction is not at equilibrium and will proceed to make more products to reach equilibrium.
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
K is the constant of a certain reaction when it is in equilibrium, while Q is the reaction quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
For the given chemical reaction:
The expression for 
is written as:
![Q=\frac{[HI]^2}{[H_2]^1[I_2]^1}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5E1%5BI_2%5D%5E1%7D)
![Q=\frac{[0.0890]^2}{[0.215]^1[0.498]^1}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5B0.0890%5D%5E2%7D%7B%5B0.215%5D%5E1%5B0.498%5D%5E1%7D)
Given : = 54.8
Thus as 
, the reaction will shift towards the right i.e. towards the product side.
Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. In neutral substances that contains atoms of one element the oxidation number of an atom is zero. Thus atoms in O2, Ni2, and aluminium all have oxidation number of zero.
In this case, Ni2, the oxidation number of Ni atom is zero,
for NiO4-, assuming oxidation number of Ni is x
(x ×1) + (-2 × 4) = -1
x = + 7
Therefore, the oxidation number goes from 0 to +7
Answer:
4.86×10^23 molecule of Pb
Explanation:
Based on that equation, for every 2 moles of ammonia, you get 3 moles of lead.
So:
2 mol NH3/ 3 mol Pb
Using this ratio we can find the amounts of either molecule. Given 5.38 mol NH3:
(5.38 NH3)(3 Pb/ 2 NH3) = (5.38)(3/2) mol Pb = 8.07 mol Pb
Then, we just need to use Avagadro's number to get the number of molecules.
(8.07)(6.02×10^23) = 4.86×10^23 molecule of Pb
Answer:
On the picture are all principles cited on wikipedia.
Explanation:
So the answer is
1. Environment must be exploited to improve living standards
2. Flourishing human and nonhuman life depends on diversity of life forms
Δt=
This because ε = dΦ/dt, and emf is a voltage so it can also be written as dΦ/dt = IR
Because ΔΦ= ABcosθ for each of the N loops and cosθ is just 1 here only A needs to be replaced, and it can be replaced with A=πr^2, which makes that part of the equation ΔΦ_m=N*B0*πa^2
