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steposvetlana [31]
2 years ago
6

A science class performed an investigation by evaporating a solution containing 10g of salt and 50ml of water. How much salt wou

ld you expect to find
in the cup at the end of the investigation?
Chemistry
1 answer:
creativ13 [48]2 years ago
5 0

Answer:

Approximately 10 g due to some experimental errors..

Explanation:

Hello,

In this case, since evaporation accounts for the removal of the solvent of a solution composed by a solvent and a solute via boiling it, we can see here that the solute is the salt and the solvent is the water and by performing an evaporation the 50 mL water need to be boiled; therefore at the end of the experiment, approximately 10 g of the salt are obtained as a solid product, but in some cases we could obtain more than such amount if the evaporation was not complete or less than it if decrepitation (spitting out of the solute due to the heat) occurs as the solid could "jump" out the recipient in which the experiment is carried out.

Best regards.

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The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 375 kJ/mol and the change in enthalpy for the reaction
HACTEHA [7]
Answer: 625 kj/mol

Explanation:

As shown below this expression gives the activation energy of the reverse reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

1) The activation energy, EA is the difference between the potential energies of the reactants and the transition state:

EA = energy of the transition state - energy of the reactants.

2) The activation energy of the forward reaction given is:

EA = energy of the transition state - energy of  [ NO2(g) + CO(g) ] = 75 kj/mol

3) The negative enthalpy change - 250 kj / mol for the forward reaction means that the products are below in the potential energy diagram, and that the potential energy of the products, [NO(g) + CO2(g) ] is equal to 375 kj / mol - 250 kj / mol = 125 kj/mol

4) For the reverse reaction the reactants are [NO(g) + CO2(g)], and the transition state is the same than that for the forward reaction.

5) The difference of energy between the transition state and the potential energy of [NO(g) + CO2(g) ] will be the absolute value of the change of enthalpy plus the activation energy for the forward reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

EA reverse reaction = 375 kj / mol + |-250 kj/mol | = 375 kj/mol + 250 kj/mol = 625 kj/mol.

And that is the answer, 625 kj/mol
4 0
2 years ago
3. In what grade level do students grow the quickest?
Vadim26 [7]

Answer:

Independent Variable: Grade Level

Dependent Variable: Growth in height

Hypothesis: Students in [Insert the grade level you believe will grow the quickest here] will experience the quickest growth in height.

Explanation:

Independent variables are the factors in which you manipulate to gain your results, in this case you would be changing the grade level you would observe to see the height.

Dependent variables are the factors that respond to changes in the independent variables. You don't control these events, you simply observe them. In this case, you merely observe the growth in height in accordance to the different grade levels you observe.

For the hypothesis, you would create your own hypothesis based on a guess you have. You create a hypothesis not based on the data, but on what you believe will be correct before doing the experiment. It doesn't have to be the correct answer, but just your thoughts.

3 0
2 years ago
What is the balanced chemical equation for the reaction used to calculate ΔH∘f of SrCO3(s)?
Igoryamba

Answer :

Standard enthalpy of formation : It is defined as the enthalpy change for the reaction that forms one mole of compound from its elements. All the substances in their standard states.

The balanced chemical equation for the reaction is,

Sr(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow SrCO_3(s)

In the balance reaction, Strontium (Sr), Carbon (C) and Strontium carbonate SrCO_3 are in solid state and oxygen is in gaseous state.

5 0
2 years ago
How much heat is lost when changing 65 g of water vapor (H2O) at 421 K to ice at 139 K?
poizon [28]

The heat change will be

Moles of water = mass / Molar mass = 65/ 18 = 3.61 mol

specific heat of ice =2.09J /g C

specific heat of water = 4.184 J/g C

Specific heat of vapour= 2.01 /g C

Heat of fusion = 3.33X10⁵ J /kg = 333 J /g

Heat of vaporization = 2.26 X10⁶J/kg = 2260J/g

Q1 = heat change when vapours get cooled to 373.15 K

Q2 = heat change when vapours get converted to liquid water

Q3 = heat change when liquid water cools to 273.15 K

Q4= heat change when liquid water freezes to ice

Q5= heat change when ice cools from 273.15K to 139 K

Q1= mass of water X specific heat of vapours X change in temperature

Q1 = 65 X 2.01 /g C X (421-373.15) = 6251.60 J = 6.252 kJ

Q2 = heat of vaporization X mass = 2260 X 65 = 146900 = 146.9 kJ

Q3 = mass X specific heat of water X change in temperature =

Q3 = 65 X 4.184 X (373.15-273.15) = 65 X 4.184 X 100 = 27196 J = 27.196kJ

Q4 = heat of fusion X mass =333X65 = 21645 J = 21.645 kJ

Q5 =  mass X specific heat of ice X change in temperature

Q5 = 65 X 2.09 X (273.15-139) = 18224.3 J = 18.224 kJ

Total energy = 6.252 +146.9+27.196+ 21.645+ 18.224 = 220.217

As this is energy released so it will be expressed in negative

-220.217

from the given options the correct answer will be -219.4 kJ

The answer is little different as the reference values of specific heats or enthalpy may vary.

3 0
2 years ago
Why does 4.03/0.0000035 = 1.2 x 106, instead of a different number of significant figures?
jasenka [17]

Explanations:- As per the significant figures rule, In multiplication and division, we go with least number of sig figs.

4.03 has three sig figs where as 0.0000035 has two sig figs only, The zeros in this number are not sig figs as they are just holding the place values. As the least number of sig figs here is two, the answer needs to be reported with two sig figs only.

\frac{4.03}{0.0000035}=1.2*10^6



4 0
2 years ago
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