In two or more complete sentences explain how to balance the chemical equation and classify its reaction type. ___P4 + ___O2 ⟶ _
2 answers:
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Answer:
0.008945 atm
Explanation:
In the reaction:
2H2S(g) ⇌ 2 H2(g) + S2(g)
Kp is defined as:
<em>Where P is the pressure of each compound in equilibrium.</em>
If initial pressure of H2S is 3.00atm, concentrations in equilibrium are:
H2S = 3.00 atm - 2X
H2 = 2X
S2: = X
Replacing:
0 = 4X³ - 1.28x10⁻⁶X² + 1.92x10⁻⁶X - 2.88x10⁻⁶
Solving for X:
X = 0.008945 atm
As in equilibrium, pressure of S2 is X, <em>pressure is 0.008945 atm</em>
Answer: 3
Explanation: This is a radioactive decay and all the radioactive process follows first order kinetics.
Equation for the reaction of decay of radioisotope follows:
By the stoichiometry of above reaction,
1 mole of is produced by 1 mole
So, 0.17 moles of will be produced by =
Amount of
decomposed will be = 0.17 moles
Initial amount of will be = Amount decomposed + Amount left = (0.17 + 0.024)moles =0.194 moles
where,
a = amount of reactant left after n-half lives = 0.024
= Initial amount of the reactant = 0.194
n = number of half lives= ?
Putting values in above equation, we get:
Therefore, 3 half lives have passed.