Explanation:
Formula for work done is as follows.
W = 
where, k = proportionality constant = 
d = separation distance = 0.45 nm = 
Now, we will put the given values into the above formula and calculate work done as follows.
W =
= ![\frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}](https://tex.z-dn.net/?f=%5Cfrac%7B-%5B8.99%20%5Ctimes%2010%5E%7B9%7D%20Jm%2FC%5E%7B2%7D%20%5Ctimes%203.2%20%5Ctimes%2010%5E%7B-19%7D%20C%20%5Ctimes%20-3.2%20%5Ctimes%2010%5E%7B-19%7D%20C%5D%7D%7B0.25%20%5Ctimes%2010%5E%7B-9%7D%20m%7D)
= 
Thus, we can conclude that work required to increase the separation of the two ions to an infinite distance is 
.
Answer:
ΔH=15000
J = 15KJ
Explanation:
In this exercise you have find the enthalpy of reaction this is the difference between enthalpy of reactans and products,
For the following equation
H2A(aq) + 2 BOH(aq) → B2A(aq) + 2 H2O(l)
We know that 0.20 moles of BOH reacted with excess amount of H2A solution and 1500. J
so,
(2mol/0,2mol)*1500J=15000J
for de reactions exothermics tha enthalpy is negative so:
ΔH=15000
J = 15KJ
<u>Answer:</u> The value of 
for the reaction at 690 K is 0.05
<u>Explanation:</u>
We are given:
Initial pressure of 
= 1.0 atm
Total pressure at equilibrium = 1.2 atm
The chemical equation for the decomposition of phosgene follows:
Initial: 1 - -
At eqllm: 1-x x x
We are given:
Total pressure at equilibrium = [(1 - x) + x+ x]
So, the equation becomes:
![[(1 - x) + x+ x]=1.2\\\\x=0.2atm](https://tex.z-dn.net/?f=%5B%281%20-%20x%29%20%2B%20x%2B%20x%5D%3D1.2%5C%5C%5C%5Cx%3D0.2atm)
The expression for for above equation follows:
Putting values in above equation, we get:
Hence, the value of for the reaction at 690 K is 0.05
What you need to do is find 1/8 of 50
you can just divide 50 by 8 to get 6.25
so now you have to find how many days it will take till there are 6.25 grams of iodine left
every 8.1 days its mass is split in half
so start splitting it in half and every time you do, you add 8.1 days
50/2 =25 8.1
25/2 =12.5 + 8.1
12.5/2= 6.25 +8.1
now you have reached 1/8 of the original amount of Iodine-131
so to find how long it took just add 8.1+8.1+8.1
(this is the same as 8.1x3)
which equals 24.3
it will take 24.3 days for Iodine 131 to decay to 1/8 of its original mass.
(good luck on the regent if thats what your studying for :)
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