According to Graham's law, the rate of effusion of a gas is inversely proportional to square root of its molecular weight.
This can be represented as follows.
Rate of effusion ∝ 1/√M
Therefore to find which gas has highest rate of effusion, we will find out the molar masses of the given compounds. The gas that is lighter in weight would have highest rate of effusion.
1) Molar mass of oxygen (O₂) is 32 g and that of H₂ is 2.01 g . Therefore H₂ would have highest rate of effusion
2) Molar mass of methane is 16.05 [12.01 + 4 (1.01)] g and that of CCl₄ [ 12 + 4(35.45) ] is 154 g. Therefore methane will have highest rate of effusion
3) Molar mass of N₂ is 28 g and molar mass of NH₃ is [ 14 + 3(3.01) ] = 17.03 g.
Therefore NH₃ will have highest rate of effusion.
4) Molar mass of F₂ is 38 g and that of Cl₂ is 71 g. Therefore F₂ will have highest rate of effusion
The answer is D only metals are shiny and highly malleable
The mathematical expression for heat capacity at constant pressure is given as:
(1)
where, Q = heat capacity
= molar heat capacity at constant pressure
= change in temperature
n = number of moles
Therefore,
= 
= 
Number of moles =
=
= 0.186 mole
Put the values in formula (1)
(conversion of degree Celsius into kelvin)
=
= 6.32 J /mol K
Hence, molar heat capacity of benzene at constant pressure = 
Answer:
strongest oxidizing agent: 
weakest oxidizing agent: 
strongest reducing agent: Y
weakest reducing agent: X
will oxidize Z
Explanation:
The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.
Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.
Order of reduction potential:

So, strongest oxidizing agent: 
weakest oxidizing agent: 
strongest reducing agent: Y
weakest reducing agent: X
As reduction potential of the half cell
is higher than the reduction potential of the half cell
therefore
will oxidize Z into
and itself gets converted into X.