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kifflom [539]
2 years ago
9

Draw a second resonance structure for the following ion (be sure to include the charges and all lone pairs)... + ..N=N=N <---

----------->.. ..

Chemistry
1 answer:
joja [24]2 years ago
8 0

Answer:

Explanation:

Resonance structure occurs in an organic compound that undergoes resonance effects. This resonance effect is sometimes called the mesomeric effect helps to increases the stability of organic compounds that have alternating single bonds and double bonds.

The second resonance structure diagram for the ion given in the question can be found in the attached diagram below.

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An element has six valence electrons available for bonding which group of the periodic table does this element most likely belon
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Elements in groups 16 has six valance electrons.
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For each pair of gases, select the one that most likely has the highest rate of effusion. Use the periodic table if necessary. O
madreJ [45]

According to Graham's law, the rate of effusion of a gas is inversely proportional to square root of its molecular weight.

This can be represented as follows.

Rate of effusion ∝  1/√M

Therefore to find which gas has highest rate of effusion, we will find out the molar masses of the given compounds. The gas that is lighter in weight would have highest rate of effusion.

1) Molar mass of oxygen (O₂) is 32 g and that of H₂ is 2.01 g . Therefore H₂ would have highest rate of effusion

2) Molar mass of methane is 16.05 [12.01 + 4 (1.01)] g and that of CCl₄ [ 12 + 4(35.45) ] is 154 g. Therefore methane will have highest rate of effusion

3) Molar mass of N₂ is 28 g and molar mass of NH₃ is [ 14 + 3(3.01) ] = 17.03 g.

Therefore NH₃ will have highest rate of effusion.

4) Molar mass of F₂ is 38 g and that of Cl₂ is 71 g. Therefore F₂ will have highest rate of effusion


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2 years ago
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A substance is highly malleable and has a shiny luster. Which of the following best explains the probable position of the substa
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It takes 330 j of energy to raise the temperature of 14.6 g of benzene from 21.0 °c to 28.7 °c at constant pressure. What is the
Akimi4 [234]

The mathematical expression for heat capacity at constant pressure is given as:

Q=n\times C_{p}\times \Delta T   (1)

where, Q = heat capacity

C_{p} =  molar heat capacity at constant pressure

\Delta T = change in temperature

n = number of moles

Therefore, \Delta T = 28.7^{o}C-21^{o}C

= 7.7 ^{o}C

Number of moles  =\frac{given mass in g}{molar mass}

= \frac{14.6 g }{78.11 g/mol}

= 0.186 mole

Put the values in formula (1)

330 J=0.186 mole\times C_{p}\times (7.7 ^{o}C+ 273) (conversion of degree Celsius into kelvin)

C_{p} = \frac{330 J}{0.186 mole\times 280.7 K}

= \frac{330 J}{52.2102 mole K}

= 6.32 J /mol K

Hence, molar heat capacity of benzene at constant pressure  = 6.32 Jmol^{-1} K^{-1}

6 0
2 years ago
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
olya-2409 [2.1K]

Answer:

     strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

     X^{+} will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

                       E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)

So, strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

As reduction potential of the half cell X^{+}\mid X is higher than the reduction potential of the half cell Z^{3+}\mid Z therefore X^{+} will oxidize Z into Z^{3+} and itself gets converted into X.

     

5 0
2 years ago
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