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svp [43]
2 years ago
13

Radioactive elements decay at a know rate known as half-life. Choose all of the correct statements concerning half-life. Carbon-

14 has a half-life of 5,730 years. A 30 gram sample will be 10 grams after 5,730 years. Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years. Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years. Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. Lead-202 has a half-life of 52,500 years. The original sample must have been 120 grams if you have a 60 gram sample after 105,000 years.
Chemistry
2 answers:
Lera25 [3.4K]2 years ago
8 0

Answer:

-Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years.

-Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years.

Explanation:

9966 [12]2 years ago
6 0

Explanation:

Half life is simply the amount of time it takes for half of a substance to decompose.

Options;

- Carbon-14 has a half-life of 5,730 years. A 30 gram sample will be 10 grams after 5,730 years. This is incorrect. After 5730 years, 15g of the sample ought to remain.

- Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years. This is correct. 3 * 76000 = 228,000

- Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years. This is incorrect. Mass after 3 half lives (27/9) = 9.5 (38 / 2 / 2)

- Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. This is incorrect. Mass after 4 half lives (6 / 1.5) = 2.5 gram (40 / 2 / 2 /2 / 2)

- Lead-202 has a half-life of 52,500 years. The original sample must have been 120 grams if you have a 60 gram sample after 105,000 years. This is incorrect. Original sampe = 240 gram. So after 2 half lives (105,000/52500), mass left = 60 (240 / 2 /2)

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Answer:

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Explanation:

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H₂(g) → 2H⁺ + 2e⁻

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By the Faraday law, 1 mol of electrons produces 96500 C of charge, thus:

1 mol --------------- 96500 C

1.026x10⁻³ mol ---- x

By a simple direct three rule:

x = 99.009 C

The current is the charge divided by the time. So, for 1 min = 60 s,

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A buffer is prepared by adding 100 mL of 0.50 M sodium hydroxide to 100 mL of 0.75 M propanoic acid. Is this a buffer solution,
Yanka [14]
The answer: is yes, It is a buffer solution.

first, we need to get moles of sodium hydroxide and propanoic acid:

moles NaOH = molarity * volume 
                       
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moles propanoic acid = molarity * volume

                                     = 0.75 M * 0.1 L = 0.075 moles

[NaOH] at equilibrium = 0.05 m

[propanoic acid ] at equilibrium = 0.075 - 0.05 = 0.025 m

when Pka for propanoic acid (given) = 4.89 

so by substitution:

∴PH = Pka + ㏒[NaOH]/[propanoic acid ]

∴ PH = 4.89 + ㏒ 0.05 / 0.025

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For each case below, identify the most likely value for x: a. BHx b. CHx c. NHx d. CH2Clx
Snezhnost [94]

Answer:

BHx, x=3

CHx, x=4

NHx, x=3

CH2Clx, x=2

Explanation:

We have to know that the value of x must depend on the valency of the central atom. If we look at each of the species;

Boron has a common valency of 3

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The valency of each elements will determine the most likely value of x as outlined in the answer above.

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