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2 years ago

given that the molar mass of Na2SO4 × nH2O is 322.1 g/mol calculate the number of moles of water in this hydrate

1 answer:

7 0

The molar mass of anhydrous Na₂SO₄ = [2(23) + 32 + 4(16)]
= 142 g/mol

If the molar mass of hydrated Na₂SO₄ = 322 g/mol

Since hydrated salt = Anhydrous Salt + Water

Then the mass of hydration (Water)= 322 g/mol - 142 g/mol
= 180 g/mol

Since the molar mass of water itself is 18 g/mol
⇒ Moles of water = 180 g/mol ÷ 18g/mol
= 10

Thus n = 10; the formula of the hydrated salt is Na₂SO₄ · 10H₂O (Sodium Sulphate Decahydrate)

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Two glasses labeled A and B contain equal amounts of water at different temperatures. Kim put an antacid tablet into each of the

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Answer:

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Solubilities of solutes are enhanced when the temperature is increased.

From the experiment conducted,

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If a dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, How many bushels of apples are in 1.0 Kg of apples

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2 years ago

Item 5 A solution of methanol, CH3OH, in water is prepared by mixing together 128 g of methanol and 108 g of water. The mole fra

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Answer:

Mole fraction of methanol will be closest to 4.

Explanation:

Given, Mass of methanol = 128 g

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The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

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$Moles= \frac{128\ g}{32.04\ g/mol}$

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Given, Mass of water = 108 g

Molar mass of water = 18.0153 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{108\ g}{18.0153\ g/mol}$

$Moles\ of\ water= 5.995\ mol$

So, according to definition of mole fraction:

$Mole\ fraction\ of\ methanol=\frac {n_{methanol}}{n_{methanol}+n_{water}}$

$Mole\ fraction\ of\ methanol=\frac{3.995}{3.995+5.995}=0.39989$

<u>Mole fraction of methanol will be closest to 4.</u>

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2 years ago

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Answer:

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Explanation:

I think you mean this

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