Approximately ____ days have passed when 20% of Cobalt (Co) remains? A) 19 B) 20 C) 21 D) 29
1 answer:
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Answer : The exit temperature of the product is,
Explanation :
Total heat = Heat lost by liquid + Latent heat of fusion + Heat lost by frozen
where,
Q = Total heat = 6000 kJ
m = mass of product = 15 kg
= specific heat of liquid =
= latent heat of fusion =
= specific heat of frozen =
= initial temperature of liquid =
= final temperature of liquid =
= initial temperature of frozen = ?
= final temperature of frozen =
Now put all the given value in the above expression, we get:
Thus, the exit temperature of the product is,