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tester [92]
2 years ago
14

A student places 1.38g of unknown metal at 99.6C into 60.50g of water at 22.1C. The entire system reaches a uniform temperature

at 31.6C. Calculate the specific heat of the metal
Chemistry
1 answer:
stiv31 [10]2 years ago
8 0

Explanation:

Heat energy lost by metal = Heat energy gained by water.

(0.00138kg) * c * (99.6-31.6) = (0.006050kg) * 4.148 * (31.6-22.1)

c = 2.541J/kg°C

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If a solution at pH 5 undergoes a 1000-fold increase in [OH-], what is the resulting pH?
lara31 [8.8K]
<span>336*280 i believe... i hope  this helps 

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7 0
2 years ago
A 14.3-cm3 sample of tin has a mass of 0.104 kg.
VladimirAG [237]
This is a true statement if it is density you are looking for... Density problem.....

Density is the ratio of the mass of an object to its volume.
D = m / V
D = 104g / 14.3 cm³ = 7.27 g/cm³ .............. to three significant digits

The conventions for the units of density is that grams per cubic centimeter (g/cm³) are usually used for solids, but will work for anything. Grams per milliliter (g/mL) are usually used for liquids and grams per liter (g/L) are for gases. Therefore, by convention, the units for tin (a solid) should be in grams per cubic centimeter.

Since 1 mL is equivalent to 1 cm³, then the density could be expressed as 7.27 g/mL.

The accepted value for the density of tin is 7.31 g/cm³
7 0
2 years ago
How many moles are in 19.6 g of Sodium (Na)? And the conversion factor?
Snezhnost [94]

Answer:

n=0.852 moles

Explanation:

Given mass is, m = 19.6 g

The molar mass of sodium is, M = 22.99 u

We need to find the no of moles in 19.6 of Sodium. We know that, no of moles is equal to given mass divided by molar mass.

n=\dfrac{m}{M}\\\\n=\dfrac{19.6}{22.99}\\\\n=0.852

So, there are 0.852 moles in 19.6 g of Sodium.

6 0
2 years ago
The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing t
lubasha [3.4K]

Answer:

The pressure of  H₂(g) = 741 torr

Explanation:

Given that:

The atmospheric pressure measured in the lab  = 765 torr

The vapor pressure of water = 24 torr

By applying Dalton's Law of Partial Pressure :

P_{total} = P_{H_2}+P_{H_2O}

Making The Pressure inside the tube due to the H₂(g) the subject of the formula :

we have:

P_{H_2} = P_{total} -  P_{H_2O}

= (765 -24) torr

= 741 torr

Therefore; the pressure of  H₂(g) = 741 torr

4 0
2 years ago
Question 1(Multiple Choice Worth 3 points)
GarryVolchara [31]

Answer:

mass molar of  gas (Mw):

Mw = 107 g/mol

Explanation:

∴ m gas = 3.82 g

∴ V gas = 0.854 L

∴ T = 302 K

∴ P = 1.04 atm

ideal gas:

  • PV = RTn

∴ n = m / Mw

⇒ PV = RTm/Mw

⇒ Mw = RTm / PV

⇒ Mw = ((0.082 atm.L/K.mol)*(302 K)*(3.82 g)) / ((1.04 atm)*(0.854 L)

⇒ Mw = 106.51 g/mol ≅ 107 g/mol

8 0
2 years ago
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