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tester [92]
2 years ago
14

A student places 1.38g of unknown metal at 99.6C into 60.50g of water at 22.1C. The entire system reaches a uniform temperature

at 31.6C. Calculate the specific heat of the metal
Chemistry
1 answer:
stiv31 [10]2 years ago
8 0

Explanation:

Heat energy lost by metal = Heat energy gained by water.

(0.00138kg) * c * (99.6-31.6) = (0.006050kg) * 4.148 * (31.6-22.1)

c = 2.541J/kg°C

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Which statement BEST describes how a golf club does "work" on a golf ball?
garri49 [273]

Answer:

C

Explanation:

It looks pretty reasonable to me

8 0
1 year ago
Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as
klio [65]

  The empirical   formula  of hydrocarbon is C₃H₈

The  molecular formula of hydrocarbon   is C₆H₁₆


<u><em> Empirical  formula  calculation</em></u>

Hydrocarbon  contain  carbon and hydrogen

  Step 1:  find the  mass  carbon (C) in carbon dioxide (CO₂)  and hydrogen (H )  in water

mass of  of element = molar mass  of element/ molar mass molecule x total mass of    molecule

From periodic table the molar mass  of C =12,    for CO₂ = 12+( 16 x2) =44 g/mol,     for H = 1.00 g/mol,    for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom  of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H  is therefore =  2/18 x 1.442 =0.1602 g


Step 2:  find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060  moles

moles of H  =  0.1602÷ 1 g/mol = 0.1602 moles


Step 3: find the mole ratio  of C and H by dividing  each  mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

  For H = 0.1602/0.06 =2.67

multiply   by 3  to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈


<u><em>The molecular formula calculation</em></u>

[C₃H₈]n  = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂   = C₆H₁₆



7 0
1 year ago
Read 2 more answers
I NEED HELP ASAP, WILL MARK BRAINLEST!
Andre45 [30]

Answer:

1. 90%

2. 217.4 g O₂

3. 95.0%

4. Trial 2 ratios

Explanation:

Original: SiCl₄ + O₂ → SiO₂ + Cl₂

Balanced: SiCl₄ + O₂ → SiO₂ + 2Cl₂

Trial        SiCl₄                   O₂                    SiO₂

 1           120 g                  240 g              38.2 g

 2           75 g                   50 g                25.2 g

<u>Percentage yield for trial 1</u>

We need to get actual yield (38.2 g) and theoretical yield, in grams.

Mass to moles:

 molar mass SiCl₄: 28.09 + 4(35.45) = 169.9 g/mol

 120 g SiCl₄ x 1 mol/169.9 g = .706 mol SiCl₄

Moles to moles:

 For each mole SiCl₄, we have one mol SiO₂ based on the balanced rxn.

 .706 mol SiCl₄ = .706 mol SiO₂

Moles to mass:

 molar mass SiO₂: 28.09 + 2(16.00) = 60.09 g/mol

 .706 mol SiO₂ x 60.09g/mol = 42.44 g SiO₂

Theoretical yield:

 actual/theoretical x 100

 38.2 / 42.44 = .900 = <u>90.0% yield</u>

<u>Leftover reactant for trial 1</u>

We know oxygen is the excess reactant.

Mass to moles:

 molar mass O₂ = 32.00 g/mol

 240 g O₂ x 1 mol/32.00 g = 7.5 mol O₂

We used .706 mol SiO₂, so we also used .706 mol O₂.

 7.5 - .706 = 6.8 moles left over

Moles to mass:

 6.8 mol O₂ x 32.00g/mol =<u> 217.4 g O₂</u>

<u />

<u>Percentage yield for trial 2</u>

Mass to moles:

 molar mass SiCl₄: 169.9 g/mol

 75 g SiCl₄ x 1 mol/169.9 g = .441 mol SiCl₄

Moles to moles:

 For each mole SiCl₄, we have one mol SiO₂ based on the balanced rxn.

 .441 mol SiCl₄ = .441 mol SiO₂

Moles to mass:

 molar mass SiO₂: 60.09 g/mol

 .441 mol SiO₂ x 60.09g/mol = 26.5 g SiO₂

Theoretical yield:

 actual/theoretical x 100

 25.2 / 26.5 = .950 = <u>95.0% yield</u>

Because the percentage yield of trial 2 is higher than that of trial 1, we know that the ratio of reactants in trial 2 is more efficient! We got a result closer to our theoretical yield.

6 0
2 years ago
What is the ratio of the concentration of potassium ions to the concentration of carbonate ions in a 0.015 m solution of potassi
tia_tia [17]

The ratio of the concentration of potassium ions (K⁺) to the concentration of carbonate ions (CO₃²⁻) = 2: 1

<h3>Further explanation</h3>

Stochiometry in Chemistry studies about chemical reactions mainly emphasizes quantitative, such as the calculation of volume, mass, amount, which is related to the number of actions, molecules, elements, etc.

Reaction equations are chemical formulations for reagents and product substances

Reaction coefficients are numbers in the chemical formula of substances involved in the reaction equation. Reaction coefficients are useful for balancing reagents and products.

The reaction coefficient shows the ratio of the number of moles or molecules of the reacting substance

The ionization reaction is the reaction of the decomposition of a substance into its ions when the substance is dissolved in water.

  • Molarity (M)

Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Electrolytes will dissociate into ions when dissolved in water

While non-electrolyte solutions do not produce ions

Electrolyte solutions can be

  • 1. Electrolytes are strong if in a solution can be fully ionized usually expressed by the degree of ionization α = 1
  • 2. Electrolytes are weak if in ions the solution is only partially ionized. The degree of ionization ranges from 0 <α <1

Potassium carbonate (K₂CO₃) will dissociate into ions

K₂CO₃ ⇒ 2K⁺+ CO₃²⁻

Comparison of reaction coefficients = mole ratio = concentration ratio for the same volume, so

The mole ratio of the ions is

K⁺ : CO₃²⁻ = 2: 1

This comparison also shows the ratio of concentrations of ions: (K₂CO₃ concentration = 0.015 M)

K⁺: CO₃²⁻ = 2.0.015: 1.0.015

K⁺: CO₃²⁻ = 0.03: 0.015 = 2: 1

<h3>Learn more</h3>

the concentrations for the two ions

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The molarity of the stock solution of luminol

brainly.com/question/2814870

volume of 0.100 M Na₃PO₄

brainly.com/question/2284993

Keywords: reaction coefficients, potassium carbonate, electrolytes

3 0
2 years ago
Read 2 more answers
A student obtained a clean flask. She weighed the flask and stopper on an analytical balance and found the total mass to be 34.2
DanielleElmas [232]

Answer:

25.99mL is the volume internal volume of the flask

Explanation:

<em>To complete the question:</em>

<em>The temperature of the water was measured to be 21ºC. Use this data to find the internal volume of the stoppered flask</em>

<em />

The flask was filled with water, that means the internal volume of the flask is equal to the volume that the water occupies.

To find the volume of the water you need to find the mass and by the use of density of water at 21ºC (0.997992g/mL), you can find the volume of the flask, thus:

Mass water = Mass filled flask - Mass of clean flask

Mass water = 60.167g - 34.232g

Mass water = 25.935g of water.

To convert this mass to volume:

25.935g × (1mL / 0.997992g) =

<h3>25.99mL is the volume internal volume of the flask</h3>
3 0
1 year ago
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