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2 years ago

A waste collection tank can hold 18754 kg of methanol, which has a density of 0.788 g/cm3.

Chemistry

1 answer:

quester [9]2 years ago

3 0

Given:
Mass of methanol, m = 18754 kg
Density of methanol, ρ = 0.788 g/cm³

By definition, the volume of methanol in the collection tank is
Volume = mass/density
$= \frac{(18754 \, kg)*(10^{3} \, \frac{g}{kg}) }{(0.788 \, \frac{g}{cm^{3})} } \\ \\ =2.38 \times 10^{7} \, \frac{g}{cm^{3}}$

Answer: 2.38 x 10⁷ g/cm³

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Calculate the hydrogen ion concentration in a solution of fruit juice having a pH of 4.25.

Airida [17]

Answer:

<h3>The answer is option B</h3>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ H+ ]

To find the hydrogen ion concentration substitute the pH into the above formula and solve for the [ H+ ]

From the question

pH = 4.25

So we have

4.25 = - log [ H+ ]

<u>Find the antilog of both sides</u>

That's

We have the final answer as

<h2> $[ H+ ] = 5.6 \times {10}^{ - 5} \: M$ </h2>

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2 years ago

A sodium atom has an electron configuration of 1s22s22p63s1.if the sodium atom becomes ionized, its new electron configuration w

dezoksy [38]

Answer:

Neon

Explanation:

1s² 2s² 2p⁶ 3s¹ or [Ne] 3s¹

The outer most shell is the 3s¹.

For this atom to achieve stability, if it loses the electron in the 3s shell, it would resemble an inert element with a complete octet configuration. Therefore, the atom would be like:

1s² 2s² 2p⁶ which is the configuration of Ne

8 0

2 years ago

In November 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. The chunk of ice was e

salantis [7]

<h2>Answer:</h2>

1.58 × 10∧16 pools.

<h3>Explanation:</h3>

Given:

Length of ice berg= 98 miles = 1557716 meters

Width of iceberg = 25 miles = 40233.6 meters

Thickness of iceberg = 750 ft = 230 meters

Volume of water in a swimming pool = 24,000 gallons = 90850 liters

The volume of the ice berg:

Volume = Length . width . thickness

Volume = 1557716 . 40233.6 . 230 = 1,441, 468, 016, 5248 m3 = 1,441, 468, 016, 5248 × 10 ∧3 L.

1 pool contains liters of water: 90850 liters

1,441, 468, 016, 5248 × 10 ∧3 liters contains = 1/90850 . 1,441, 468, 016, 524.8 × 10 ∧3 .

= 1.100 . 1,441, 468, 016, 5248 × 10 ∧3 L.

= 1.58 × 10∧16 pools.

Hence 1.6 × 10∧16 pools will be filled with that chunk of ice.

4 0

2 years ago

Read 2 more answers

Consider the reaction cacn2 3 h2o → caco3 2 nh3 . how much nh3 is produced if 187 g of caco3 are produced?

shusha [124]

B ase from the reaction <span>cacn2 3 h2o → caco3 2 nh3, for every 1 mole of caco3 produced there 2 moles of nh3 being produced. to solved this, we must first convert the caco3 to moles.

mass nh3 = 187 g caco3 (1 mol caco3 / 100 g caco3 ) ( 2 mol nh3 / 1 mol caco3) ( 17 g nh3 / 1 mol nh3)

mass nh3 = 63.58 g nh3 is produced</span>

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2 years ago

Identify the Lewis acids and Lewis bases in the following reactions:

postnew [5]

Answer: 1. $H^++OH^-\rightarrow H_2O$ Lewis acid : $H^+$ , Lewis base : $OH^-$

2. $Cl^-+BCl_3\rightarrow BCl_4^-$ Lewis acid : $BCl_3$ , Lewis base : $Cl^-$

3. $K^++6H_2O\rightarrow K(H_2O)_6$ Lewis acid : $K^+$ , Lewis base : $H_2O$

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

1. $H^++OH^-\rightarrow H_2O$

As $H^+$ gained electrons to complete its octet. Thus it acts as lewis acid. $OH^-$ acts as lewis base as it donates lone pair of electrons to electron deficient specie $H^+$ .

2. $Cl^-+BCl_3\rightarrow BCl_4^-$

As $BCl_3$ is short of two electrons to complete its octet. Thus it acts as lewis acid. $Cl^-$ acts as lewis base as it donates lone pair of electrons to electron deficient specie $BCl_3$ .

3. $K^++6H_2O\rightarrow K(H_2O)_6$

As $K^+$ is short of electrons to complete its octet. Thus it acts as lewis acid. $H_2O$ acts as lewis base as it donates lone pair of electrons to electron deficient specie $K^+$ .

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2 years ago