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Mumz [18]
2 years ago
14

A waste collection tank can hold 18754 kg of methanol, which has a density of 0.788 g/cm3.

Chemistry
1 answer:
quester [9]2 years ago
3 0
Given:
Mass of methanol, m = 18754 kg
Density of methanol, ρ = 0.788 g/cm³

By definition, the volume of methanol in the collection tank is
Volume  = mass/density
               = \frac{(18754 \, kg)*(10^{3} \,  \frac{g}{kg}) }{(0.788 \,  \frac{g}{cm^{3})} }  \\ \\ =2.38 \times 10^{7} \,  \frac{g}{cm^{3}}

Answer:  2.38 x 10⁷ g/cm³
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Alexxx [7]

Answer:

Explanation:

An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.

Chemical equation:

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2) Hydrazine ( N₂H₄)  is being oxidized

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3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)

5 0
2 years ago
What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?
Anna11 [10]
Molar mass  CaCl₂ =  110.98 g/mol

Number of moles:

1 mole CaCl₂ ---------> 110.98 g
n mole CaCl2 ---------> 85.3 g

n = 85.3 / 110.98

n = 0.7686 moles of CaCl₂

Volume = ?

M = n / V

0.788 =  0.7686 / V

V = 0.7686 / 0.788

V = 0.975 L

hope this helps!
5 0
2 years ago
Microwave ovens are able to cook food because they increase the_______ of water molecules in the food.
Whitepunk [10]

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4 0
2 years ago
Which of the following represents a propagation step in the monochlorination of methylene chloride (CH2Cl2)?a. CHCl3 + Cl. Right
svetlana [45]

Answer:

B = CHCl2 + Cl2 --> CHCl3 + Cl

Explanation:

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Free radical chlorination is divided into 3 steps which are:

The initiation step

The propagation step

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So in reference to the question, propagation step involves two steps.

The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.

The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.

You would find in the attachment the 2 step mechanism.

3 0
2 years ago
A 0.25 m solution of the sugar sucrose (c12h22o11) in water is tested for conductivity using the type of apparatus shown. Bulb w
Anvisha [2.4K]

Sucrose is a non ionic compound. It does liberates ion when dissolved in water unlike NaCl or other salts which dissolve in water and produce respective cations and anions.

Thus if any amount of sucrose is dissolved in water, it will form non ionic aqueous solution (it will dissolve completely). Thus sucrose solution being non electrolytic will not conduct electricity in aqueous solution.

the bulb will not light up as sucrose will remain in molecular form only

6 0
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