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1 year ago

How many moles of KCl will be produced from 15.0 g of KClO3?

Chemistry

2 answers:

slega [8]1 year ago

7 0

Answer:

0.12 mol KCl

Explanation:

2 KClO3 (s) 2 KCl (s) + 3 O2 (g)

15 g x mol

x g KCl = 15 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]

x g KCl = 0.12 mol KCl

MAXImum [283]1 year ago

7 0

Answer:

0.1224 moles

Explanation:

this is a decompostion reaction

Equation of reaction

2KClO₃ → 2KCl + 3O₂

molar mass of KClO₃ =

molar mass of K = 39.09g/mol

Molar mass of Cl = 35.5g/mol

Molar mass of O = 15.99g/mol

Molar mass of KClO3 = [39 + 35.5 + (3*15.99)]

Molar mass of KClO3 = 122.47g/mol

From the equation of reaction,

2 moles of KClO₃ produces 2 moles of KClO₃

But 1 mole = molar mass

1 mole of KClO₃= 122.47g

2 moles of KClO₃ = 2 * 122.47 = 244.94g

If 244.94g of KClO₃ produces 2 moles of KCl

15 g of KClO₃ will produce x mole of KCl

x = (15 * 2) / 244.94

x = 0.1224moles

15g of KClO₃ will produce 0.1224moles of KCl

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