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PIT_PIT [208]
2 years ago
7

How many moles of KCl will be produced from 15.0 g of KClO3?

Chemistry
2 answers:
slega [8]2 years ago
7 0

Answer:

0.12 mol KCl

Explanation:

2 KClO3 (s)   2 KCl (s) + 3 O2 (g)

15 g                x mol

x g KCl = 15 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]

x g KCl = 0.12 mol KCl

MAXImum [283]2 years ago
7 0

Answer:

0.1224 moles

Explanation:

this is a decompostion reaction

Equation of reaction

2KClO₃ → 2KCl + 3O₂

molar mass of KClO₃ =

molar mass of K = 39.09g/mol

Molar mass of Cl = 35.5g/mol

Molar mass of O = 15.99g/mol

Molar mass of KClO3 = [39 + 35.5 + (3*15.99)]

Molar mass of KClO3 = 122.47g/mol

From the equation of reaction,

2 moles of KClO₃ produces 2 moles of KClO₃

But 1 mole = molar mass

1 mole of KClO₃= 122.47g

2 moles of KClO₃ = 2 * 122.47 = 244.94g

If 244.94g of KClO₃ produces 2 moles of KCl

15 g of KClO₃ will produce x mole of KCl

x = (15 * 2) / 244.94

x = 0.1224moles

15g of KClO₃ will produce 0.1224moles of KCl

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describe the energy inputs and outputs for the campfire. Use the law of conservation of energy to construct a valid qualitative
-Dominant- [34]

Answer:

The essence including its particular subject is outlined in the following portion mostly on clarification.

Explanation:

  • The energy throughout the campfire comes from either the wood's latent chemical energy until it has been burned to steam up and launch up across the campfire. The electricity generation for something like a campfire seems to be in the context including its potential chemical energy which is contained throughout the firewood used only to inflame the situation.
  • The energy output seems to be in the different types of heat energy radiating across the campfire, laser light generated off by the blaze, and perhaps a little number of electrical waves, registered throughout the firewood cracking whilst they combust throughout the blaze.

and,

chemical energy ⇒ heat energy + light energy + sound energy

6 0
1 year ago
If an ionic compound were composed of a4+ and b−, which unit cell structure would give a neutral compound?
Ymorist [56]
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4 0
1 year ago
If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint:
Andrew [12]

Answer:

Mass of CuSO4.H2O obtained: m_{total}=19.52 g

Explanation:

The molecular weight of the salt is: M=159.5 g/mol

<u>In the solution</u>: 12.5 g of CuSO4

In moles: n=\frac{12.5 g}{159.5 g/mol}=0.078 mol

<u>Mass of wate</u>r:

5 moles of water per mol of salt: m=\frac{5mol}{1mol}*0.078mol*\frac{18g}{mol}=7.02 g

Mass of CuSO4.H2O obtained: m_{total}=12.5 g + 7.02 g=19.52 g

7 0
2 years ago
Solid aluminum metal and diatomic chlorine gas react spontaneously to form a solid product. Give the balanced chemical equation
ValentinkaMS [17]

When solid aluminum metal is reacted with diatomic chlorine gas, solid aluminum chloride is formed. This reaction is an example of synthesis or chemical combination in which two elements, aluminum and chlorine combine to form a new compound aluminum chloride.

Word equation: Aluminum (s)+ Chlorine (g)---> Aluminum chloride(s)

Molecular formula of the product formed is AlCl_{3}.

Therefore the balanced chemical equation representing the reaction of solid aluminum with gaseous dichlorine can be represented as,

2Al(s) + 3Cl_{2}(g)-->2AlCl_{3}(s)

8 0
2 years ago
Exactly 56 grams of iron is mixed with 156 grams of oxygen. The elements are heated and they react. What best describes which re
Mars2501 [29]

Answer:

Explanation:

The chemical expression for the reaction between iron and oxygen is:

4Fe(s)  +  3O₂ (g)  \to 2Fe₂O₃ (s)

The number of moles of Fe = mass of Fe/ molecular mass of Fe

The number of moles of Fe = 56 g/ 55.845 g/mol

The number of moles of Fe = 1.002 moles of Fe

The number of moles of oxygen = mass of oxygen/ molecular mass of oxygen

The number of moles of oxygen = 156 g /32 g/mol

The number of moles of oxygen = 4.875 moles of oxygen

Assume that Fe is the limiting reactant, the number of Fe₂O₃ can be calculated as:

moles of Fe₂O₃ = 1.002 mole of Fe × 2 moles of Fe₂O₃/ 4 moles of Fe

moles of Fe₂O₃ = 0.501 mole of Fe₂O₃

Assume that O₂ is the limiting factor, the number of Fe₂O₃ is:

moles of Fe₂O₃ = 4.875 moles of O₂ × 2 moles of Fe₂O₃/ 3 moles of O₂

moles of Fe₂O₃ = 3.25 mole of Fe₂O₃

Thus, after the reaction is complete, Fe and O₂ contain different moles of Fe₂O₃. Only Fe gets consumed in the reaction and it is the limiting factor.

8 0
1 year ago
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