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2 years ago

Calculate the mass in grams of 1.32x10^20 uranium atoms

1 answer:

6 0

<span>Uranium has an atomic weight of 238.03 g/mol. We have 1.32x10^20 atoms of uranium. We must convert this to moles by dividing Avogadro's number 6.022x10^23 atoms/mol. (1.32x10^20atoms)/(6.022x10^23atoms/mol) 2.19x10^-4moles of Uranium Now multiply this by the atomic weight of Uranium. 2.19x10^-4mol*238.03g/mol Grams of Uranium = .0522g</span>

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Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d

PilotLPTM [1.2K]

Answer:

k = 23045 N/m

Explanation:

To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:

$K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2$ (1)

M: mass of the car = 1050 kg

k: spring constant = ?

v: velocity of the car = 8 km/h

x: maximum compression of the spring = 1.5 cm = 0.015m

You solve the equation (1) for k. But first you convert the velocity v to m/s:

$v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}$

$k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}$

The spring constant is 23045 N/m

3 0

2 years ago

How many grams of the excess reagent are left over when 6.00g of CS2 gas react with 10.0g of Cl2 gas in the following reaction:

WARRIOR [948]

Answer:

CS₂ = 2.43 g

Explanation:

Data Given:

CS₂ gas = 6.00g

Cl₂ = 10.0g

Reaction Given:

CS₂(g) + 3Cl₂(g) --------> CCl₄(l) + S₂Cl₂(l)

Solution

Limiting Reagent :

The reactant which is less in amount control the amount of product and know as limiting reagent.

Excess Reagent:

The amount of reactant which are in excess and leftover at the end of reaction and product formed.

Now we have to find the reactant that is in excess

For this we will look at the Reaction

CS₂ + 3Cl₂ --------> CCl₄ + S₂Cl₂

1 mol 3 mol 1 mol 1 mol

we come to know from the above reaction that

1 mole of CS₂ react with 3 mole of Cl₂ to produce 1 mole of CCl₄ and 1 mole of S₂Cl₂

Now to convert mole to mass we required molar masses

molar mass of CS₂ = 12 + 2(32)

molar mass of CS₂ = 76 g/mol

molar mass of Cl₂ = 2(35.5)

molar mass of Cl₂ = 71 g/mol

if we represent mole in grams then

CS₂ + 3Cl₂ --------> CCl₄ + S₂Cl₂

1 mol (76 g/mol) 3 mol (71 g/mol)

CS₂ + 3Cl₂ --------> CCl₄ + S₂Cl₂

76 g 213 g

So,

we come to know that 76 g of CS₂ will combine with 213 g of Cl₂ to form product.

So now look for the ratio of both reactant

CS₂ : Cl₂

76 g : 213 g

1 g : 2.8 g

So, the for every one gram of CS₂ required 2.8g Cl₂

So from this details

we apply unity formula

2.8 g of Cl₂ ≅ 1 g of CS₂

10 g of Cl₂ ≅ ? g of CS₂

by doing cross multiplication

g of CS₂ = 10 x 1 / 2.8

g of CS₂ = 3.6 g

So,

10.0g of Cl₂ used 3.57 g of CS₂

It showed that 3.57 g of CS₂ used and the remaining amount of CS₂ is

Remaining amount of CS₂ = 6 - 3.57 = 2.43 g

8 0

2 years ago

Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6

Volgvan

Answer:

$2.0x10^{-5}\frac{mol}{L}$

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

$CuCl(s)\rightarrow Cu^++Cl^-$

And its equilibrium expression is:

$Ksp=[Cu^+][Cl^-]$

We can represent the molar solubility via the reaction extent as $x$ , however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

$1.0x10^{-6}=(x)(0.050+x)$

Thus, solving for $x$ , we obtain:

$1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0$

By using the quadratic equation, we obtain:

$x_1=2.0x10^{-5}M\\\\x_2=-0.05M$

Clearly, the solution is $x_1=2.0x10^{-5}M$ because no negative results are

allowed. Therefore, the molar solubility is:

$2.0x10^{-5}\frac{mol}{L}$

Best regards!

5 0

2 years ago

Object A has a temperature of 287 Kelvin, object B has a temperature of 374 Kelvin. In what direction will thermal energy flow?

Mashcka [7]

Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.

6 0

2 years ago

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Select the number of electrons each atom must gain or lose to have a full valence level. Use the periodic table if you need help

Lady bird [3.3K]

Calcium will loose one electron. Fluorine will gain one electron. Lithium will loose one electron. Argon will not loose any because it already has a full valence level. Aluminium will loose 3 electrons.

8 0

2 years ago

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