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tigry1 [53]
1 year ago
12

Suppose a metal will eject electrons from its surface when struck by yellow light. What will happen if the surface is struck wit

h ultraviolet light?
a. No electrons would be ejected.
b. Electrons would be ejected and they would have lower kinetic energy than those ejected by yellow light.
c. Electrons would be ejected and they would have the same kinetic energy by yellow light.
d. Electrons would be ejected and they would have greater kinetic energy than those ejected by yellow light.
Chemistry
1 answer:
Marizza181 [45]1 year ago
4 0

Answer:

d. Electrons would be ejected and they would have greater kinetic energy than those ejected by yellow light.

Explanation:

A formula that describes the kinetic energy of an electron ejected when a surface is truck by light is:

  • Ephoton = KineticEnergyElectron + Φ

As you see, the higher the energy of the photon striking the surface, the higher the kinetic energy of the ejected electron.

<em>Ultraviolet light has more energy than yellow light</em>, so it would cause<em> the ejected electron to have greater kinetic energy as well</em>.

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Type the correct answer in the box. Express your answer to three significant figures.
VladimirAG [237]

<u>Given:</u>

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

<u>To determine:</u>

Theoretical yield of calcium phosphate, Ca3(PO4)2

<u>Explanation:</u>

Balanced Chemical reaction-

3Ca(NO3)2 + 2Na3PO4 → 6NaNO3 + Ca3(PO4)2

Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

Given mass of Ca(NO3)2 =  96.1 g

Molar mass of Ca(NO3)2 =  164 g/mol

# moles of ca(NO3)2 = 96.1/164 = 0.5859 moles

Therefore, # moles of Ca3(PO4)2 produced = 0.0589 * 1/3 = 0.0196 moles

Molar mass of Ca3(PO4)2 = 310 g/mol

Mass of Ca3(PO4)2 produced = 0.0196 * 310 = 6.076 g

Ans: Theoretical yield of Ca3(PO4)2 = 6.08 g



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1 year ago
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the melting point of scandium fluoride is 1552°c, explain why scandium fluoride has a high melting point.​
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Answer:

Scandium(III) fluoride, ScF3, is an ionic compound. It is slightly soluble in water but dissolves in the presence of excess fluoride to form the ScF63− anion.

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What is the amount of heat released when 25g of water cools 12.5 degrees C ?
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Given: CaC2 + N2 → CaCN2 + C In this chemical reaction, how many grams of N2 must be consumed to produce 265 grams of CaCN2? Exp
weeeeeb [17]

Answer : The grams of N_2 consumed is, 89.6 grams.

Solution : Given,

Mass of CaCN_2 = 265 g

Molar mass of CaCN_2 = 80 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate the moles of CaCN_2.

\text{Moles of }CaCN_2=\frac{\text{Mass of }CaCN_2}{\text{Molar mass of }CaCN_2}=\frac{265g}{80g/mole}=3.2moles

The given balanced reaction is,

CaC_2+N_2\rightarrow CaCN_2+C

from the reaction, we conclude that

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So, 3.2 moles of CaCN_2 produces from 3.2 moles of N_2

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\text{Mass of }N_2=\text{Moles of }N_2\times \text{Molar mass of }N_2

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