Answer:
The open system evaporates the solvent in the solution
Explanation:
An open system is a system in which exchange of materials and energy can occur. If a TLC set up is left open, then the set up constitutes an open system.
During TLC, the sample is dotted on the plate and inserted into a suitable solvent. The solvent moves up the plate and achieves the required separation of the mixture.
Most of these solvents used used TLC are volatile organic compounds. Therefore, if the TLC set up is left open, the solvent will evaporate leading to poor results after running the TLC experiment.
Answer:
64.0
Explanation:
2Mg+O2 ---> 2MgO
use dimentional analysis to find the amount of moles of O2 needed first
4.00molMg x 1.00mol O2/ 2.00 mol Mg=. 2.00 mol O2
using the coefficients you can see the mole ratio for O2:Mg the mole ratio is 1:2 which is why there is 1 mole on the top for 2 moles on the bottom. The Mg would cancel and multiply 4 by 1 then divide by 2, or multipy 4 by 1/2
Now that you have the moles of O2 you use the molar mass to find the grams in 2 moles of O2
2.00 mol O2 x 32.0g/1.00 mol = 64.0 g
multiply 2 by 32
Answer:
The answer to your question is: 0.373 g
Explanation:
Data
mass = ? g
atoms = 3 x 10 ²¹
AM = 74.92 g
Process
1 mol of As ------------------ 6.023 x 10²³ atoms
x ------------------ 3 x 10 ²¹ atoms
x = 4.98 x 10⁻³ moles
1 mol ------------------------ 74.92 g
4.98 x 10⁻³ moles------- x
x = (4.98 x 10⁻³ x 74.92)/1
x = 0.373 g of As
Answer:
Explanation:
sp² hybridization is found in those compounds having double bond .
Out of the given compounds only C₂H₂Cl₂ has double bond so this compound contains carbon with sp² hybridization .
Rest have sp³ hybridization because they are saturated compounds .
Answer:
Inference — The candle stayed lit longer because the plant gave off oxygen.
Observation — The candle went out when it was placed in a closed jar.
Observation — The candle stayed lit longer in closed jar when a plant was present.
Explanation:
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