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____ [38]
1 year ago
15

When exposed to very high temperatures, metals like iron can be turned into fluids that flow and can be poured into molds. What

happens within the iron to allow it to flow?
A) The energy of the solid decreases, and the particles begin to collide with high frequency

B)The energy of the solid increases, and the particles begin to slide past each other

C)The solids collide at an increasing rate until reaching equilibrium energy

D)The particles vibrate about equilibrium in an effort to minimize energy
Chemistry
1 answer:
oksano4ka [1.4K]1 year ago
7 0

Answer: B) The energy of the solid increases, and the particles begin to slide past each other.

Explanation:

The energy of the solid matter is required to be increased so that molecules of the solid matter get separated from each other and an transition from solid matter to liquid matter occurs. The liquid components of the matter will slide past each other as they have obtain energy for fluidity. The liquid iron can be molded into any shape and the energy decreases considerably.

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If 15.6 g of hydrate are heated and only 11.7 g of anhydrous salt remain, calculate the % of water lost.
Elodia [21]

Answer:

Percent loss of water = 25%

Explanation:

Given data:

Mass of hydrated salt = 15.6 g

Mass of anhydrous salt = 11.7 g

Percentage of water lost = ?

Solution:

First of all we will calculate the mass of water in hydrated salt.

Mass of water =  Mass of hydrated salt - Mass of anhydrous salt

Mass of water = 15.6 g - 11.7 g

Mass of water = 3.9 g

Now we will calculate the percentage.

Percent loss of water = mass of water / total mass × 100

Percent loss of water = 3.9 g/ 15.6 g × 100

Percent loss of water = 25%

8 0
1 year ago
6. The half life for uranium-235 is 7.0x108 years.
kaheart [24]

Answer:

\large \boxed{4.0}

Explanation:

\text{No. of half-lives} = 2.8  \times 10^{9 } \text{ yr} \times \dfrac{\text{1 half-life}}{7.0 \times 10^{8} \text{ yr}} = \textbf{4.0 half-lives}\\\\\text{The sample went through $\large \boxed{\textbf{4.0 half-lives}}$}

4 0
2 years ago
The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution i
bija089 [108]

Answer:

110ml

Explanation:

<em>Using the dilution equation, C1V1 = C2V2</em>

<em>Where C1 is the initial concentration of solution</em>

<em>C2 is final concentration of solution</em>

<em>V1 is intital volume of solution</em>

<em>V2 is final volume of solution.</em>

From the question , C1=6M, C2=0.5M, V1=10ml, V2=?

V2 =\frac{C1V1}{C2}

V2 =\frac{10*6}{0.5}

V2 =120ml

volume of water added = final volume -initial volume

                                    = 120-10

                                   =110ml

3 0
2 years ago
Arsenic produces a blue flame when heated. Calcium produces an orange-red flame. Which of these best explains why this differenc
MrMuchimi

Flame colors are produced from the movement of the electrons in the metal ions present in the compounds. When you heat it, the electrons gain energy and can jump into any of the empty orbitals at higher levels Each of these jumps involves a specific amount of energy being released as light energy, and each corresponds to a particular color. As a result of all these jumps, a spectrum of colored lines will be produced. The color you see will be a combination of all these individual colors.

6 0
1 year ago
A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated
n200080 [17]

Answer:

The empiricial formula of the compound is BaO2

Explanation:

<u>Step 1:</u> Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

<u>Step 2: </u>Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

<u>Step 3</u>: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

<u>Step 4:</u> Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

<u>Step 5:</u> Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

<u>Step 6:</u> Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

O → 0.01625 / 0.0079 ≈ 2

(1.091 g Ba) / (137.3277 g Ba/mol) = 0.00794450 mol Ba

(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

This gives us the empirical formula of BaO2 for this compound

7 0
1 year ago
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