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krek1111 [17]
2 years ago
12

Jeff has 10 grams of water and 10 grams of vegetable oil in separate containers. Both liquids have a temperature of 24°C. Jeff h

eats both liquids over a flame for five minutes. When he’s finished, he discovers that the temperature of the oil increased more than the temperature of the water. What can Jeff conclude from this experiment? Vegetable oil is a better conductor of heat than water. Water is a better conductor of heat than vegetable oil. Vegetable oil has a higher heat capacity than water. Vegetable oil has a lower heat capacity than water. Vegetable oil is a good insulator.
Chemistry
2 answers:
Anna11 [10]2 years ago
8 0
I think the answer would be that vegetable oil is a better conductor of heat than water.
Sonbull [250]2 years ago
6 0

Answer: Vegetable oil has a lower heat capacity than water.

Explanation:

Specific heat capacity is the heat required to raise the temperature of 1 g of a substance through 1^0C.

q=m\times c\times \Delta T

q = heat absorbed

m= mass of substance

c= specific heat

\Delta T = change in temperature

As both vegetable oils and water both have same mass and have same initial temperature and absorbed same heat.

As the temperature of the oil increased more than the temperature of the water, it means the specific heat of oil is less than that of water as the heat absorbed is same.

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25 g of ethyl alcohol is dissolved in 100 ml of water (density = 0.99993 at 20 oc). what is the % w/w for the ethyl alcohol in t
vitfil [10]
<span>Percentage by mass is the amount in mass of a component in a mixture per 100 unit of mass of the total mixture. Percentage by mass is the same as  %w/w. We can determine this by dividing the mass of the solute with the total mass of the mixture. However, from the problem statement, we are given the volume of the water so there is a need to convert this value to mass by using the density of water. We calculate as follows:

Mass of solution = 100 mL (0.99993 g/mL) water + 25 g EtOH
Mass of solution = 124.993 g solution

%w/w = 25 g / 124.993 g x100
%w/w = 20% of EtOH</span>
5 0
1 year ago
Lightsticks produce light via a chemical reaction. Dropping a lightstick into hot water makes it glow A) less intensely. B) more
victus00 [196]

Answer:

B.) More intensely

Explanation:

If you immerse a lightstick in hot water, the chemical reaction will speed up. The stick will glow much more brightly but will wear out faster too.

4 0
2 years ago
Read 2 more answers
Write a chemical equation showing how this is an acid according to the arrhenius definition. express your answer as a balanced c
Alik [6]

According to Arrhenius theory, acid is a substance that releases H⁺ ions when dissolved in water.

In order to apply this theory, the substance must be soluble in water.

H₂SO₄ is highly soluble in water. It undergoes following dissociation reaction when dissolved in water.

H_{2}SO_{4}(aq)\overset{H_{2}O}{\rightarrow} 2H^{+}(aq)+ SO_{4}^{2-}(aq)

From the above equation, we can see that H₂SO₄ forms 2 H⁺ ions when dissolved in water. Therefore it behaves as an acid according to Arrhenius theory.

7 0
1 year ago
Explain how your experimental data for Rf values are, or are not, consistent with your predictions of enantiomeric and diastereo
hichkok12 [17]

Answer:

Answer is explained below.

Explanation:

As (+) menthol and (-) menthol are enantiomers whose physical properties are same except optical activity so we can expect they have similar Rf values.

Whereas diastereomers have different physical properties and different Rf values.

For example when the (+) menthol , (-) menthol, isomenthol and neomenthol undergo TLC (thin layer chromatography) the

Rf values of.(+menthol) = .447

Rf (+isomenthol) = .395

Rf (+neomenthol)= .487

Rf (-menthol) = .434

The above data shows that (+) menthol and (-) menthol have almost same Rf values and vary a little i.e 0.447 and 0.437. So we can conclude them as enantiomers

Whereas (+) menthol or (+) neomenthol or (+) isomenthol i.e 0.447 , 0.395 and 0.487 have different Rf values. We can conclude them as diasteromers.

(+) menthol and (-) menthol - enantiomers

(+) menthol and (+) neomenthol- diastereomers

(-) menthol and (+) isomenthol - diastereomers

3 0
1 year ago
Read 2 more answers
Identify the MOs that react to form cyclohexene. HOMO of 1,3-butadiene and LUMO of ethylene LUMO of 1,3-butadiene and LUMO of et
BARSIC [14]

Answer:

HOMO of 1,3-butadiene and LUMO of ethylene

HOMO of ethylene LUMO of 1,3-butadiene

Explanation:

1,3 - butadiene underogoes cycloaddition reaction with ethylene to give cyclohexene.

According to Frontier molecular orbital theory HOMO of 1,3 butadiene and LUMO of ethylene and HOMO of ethylene and LUMO of ethylene underoges (4 + 2) in thermal or photochemical condition.

6 0
1 year ago
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