Jeff has 10 grams of water and 10 grams of vegetable oil in separate containers. Both liquids have a temperature of 24°C. Jeff h
2 answers:
Answer: Vegetable oil has a lower heat capacity than water.
Explanation:
Specific heat capacity is the heat required to raise the temperature of 1 g of a substance through .
q = heat absorbed
m= mass of substance
c= specific heat
= change in temperature
As both vegetable oils and water both have same mass and have same initial temperature and absorbed same heat.
As the temperature of the oil increased more than the temperature of the water, it means the specific heat of oil is less than that of water as the heat absorbed is same.
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Answer:The molar heat of vaporization of molten lead is 178.03 kJ/mol.
Explanation:
The molar heats of fusion of lead
...(1)
The molar heats of sublimation of lead
...(2)
Adding (1) and (2)
The molar heat of vaporization of molten lead is 178.03 kJ/mol.
Answer:
See answer and picture below
Explanation:
In this case, the key to get an idea of how is the starting ether is with the final product and the empirical formula of the ether.
First, the empirical formula of the ether gives us information of the structure of the ether. This ether could be either an alkene, alkane or cycloalkane.
Alkane cannot be because alkane's formula is CnH(2n+2), so it's either an alkene or cycloalcane (CnH2n).
However, as we can see, it reacts with HI in excess, so, it cannot be an alkene because in this case the acid will react with the double bond of the ether too forming another product. This discart the fact that the ether has a double bond. So it has to be a cycloalkane.
As the innitial structure it's an ether, it should be either a cyclohexane or cyclopentane with a methyl group attached. So, how can we know which of these structures is? well, we can actually do the reaction with both reactants and see which match. In the attached picture you have the answer.
Hope this helps.
The volume of sphere can be calculated using the following formula:
Here, r is radius of the sphere which is 3.5 cm. Putting the value,
This is equal to the volume of lead, density of lead is thus, mass of lead can be calculated as follows:
m=d×V
Putting the values,
Let the mass of ore be 1 g, 68.6% of galena is obtained by mass, thus, mass of galena obtained will be 0.686 g.
Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:
m=0.686×0.866=0.5940 g
Therefore, 0.5940 g of lead is obtained from 1 g of ore for 100% efficiency, thus, for 92.5% efficiency
1 g of lead obtain from grams of ore.
Thus, 2041.2 g of lead obtain from:
Therefore, mass of ore required to make lead sphere is 3.715 kg.