is this for a test or are you genuinely interested? molality = mols sugar/kg solvent
Solve for molality
delta T = Kf*m
Solve for delta T and subtract from zero C to find the new freezing point.
or
-5.58
Answer:
Both reaction A and reaction B are non spontaneous.
Explanation:
For a spontaneous reaction, change in gibbs free energy (
) should be negative.
We know,
, where T is temperature in Kelvin scale.
Reaction A: 
As
is positive therefore the reaction is non-spontaneous.
If at a temperature T K , the reaction is spontaneous then-

or, 
or, 
or, 
So at a temperature greater than 350 K, the reaction is spontaneous.
Reaction B: 
As
is positive therefore the reaction is non-spontaneous.
If at a temperature T K , the reaction is spontaneous then-

or, 
or, 
or, 
So at a temperature greater than -16 K, the reaction is spontaneous.
Answer:
Explanation:With no acceleration the graph would be flat.
Answer: 1.
moles
2. 90 mg
Explanation:

According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus
moles of ozone is removed by =
moles of sodium iodide.
Thus
moles of sodium iodide are needed to remove
moles of 
2. 
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 0.0003 moles of ozone is removed by =
moles of sodium iodide.
Mass of sodium iodide=
(1g=1000mg)
Thus 90 mg of sodium iodide are needed to remove 13.31 mg of
.