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lesya692 [45]
2 years ago
15

An atom's atomic number is 7. Its valence is most likely ... An atom's atomic number is 7. Its valence is most likely ... 7 5 3

2 1 previous answersrequest answer
Chemistry
1 answer:
Naya [18.7K]2 years ago
3 0

The valence of an atom is defined as the number of bonds formed by the atom in the molecule.

The given atomic number is 7.

The electronic configuration of atom having atomic number 7 is:

1s^{2}2s^{2}2p^{3}

From the electronic configuration, it is clear that number of electrons in the outer most orbital (valence shell electron) is 5.

Hence, for an atom whose atomic number is 7. Its valence is 5.

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which intensive physical property is observed when droppings of a person seated inside a closed room has able to reach a person
zavuch27 [327]

Answer:

The right response will be "Speed".

Explanation:

  • Intensive or Individualized physical property becomes found when "speed" seems to be the excrement of either an individual who sits within a closed or contained environment that can hit a person one meter away after sneezing or coughing.
  • This measure seems to be "meter per second", its a intense property.
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2 years ago
When magnesium ribbon is placed in sulfuric acid, a chemical reaction takes place and heat energy is given off. Liang and Naraba
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Answer:

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6 0
1 year ago
A sample of a gas (1.50 mol) is contained in a 15.0 l cylinder. the temperature is increased from 100 °c to 150 °c. what is the
pav-90 [236]

<u>Given:</u>

Moles of gas, n = 1.50 moles

Volume of cylinder, V = 15.0 L

Initial temperature, T1 = 100 C = (100 + 273)K = 373 K

Final temperature, T2 = 150 C = (150+273)K = 423 K

<u>To determine:</u>

The pressure ratio

<u>Explanation:</u>

Based on ideal gas law:

PV = nRT

P= pressure; V = volume; n = moles; R = gas constant and T = temperature

under constant n and V we have:

P/T = constant

(or) P1/P2 = T1/T2 ---------------Gay Lussac's law

where P1 and P2 are the initial and final pressures respectively

substituting for T1 and T2 we get:

P1/P2 = 373/423 = 0.882

Thus, the ratio of P2/P1 = 1.13

Ans: The pressure ratio is 1.13


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2 years ago
Commercially available hot packs are simple in design: a pouch with water on one side, isolated by a barrier from a specific sal
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3 0
2 years ago
A 0.1153-gram sample of a pure hydrocarbon was burned in a C-H combustion train to produce 0.3986 gram of CO2and 0.0578 gram of
Mars2501 [29]

<u>Answer:</u> The mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=0.3986g

Mass of H_2O=0.0578g

Mass of sample = 0.1153 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.3986 g of carbon dioxide, \frac{12}{44}\times 0.3986=0.1087g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.0578 g of water, \frac{2}{18}\times 0.0578=0.0066g of hydrogen will be contained.

To calculate the percentage composition of a substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of sample}}\times 100      ......(1)

  • <u>For Carbon:</u>

Mass of sample = 0.1153 g

Mass of carbon = 0.1087 g

Putting values in equation 1, we get:

\%\text{ composition of carbon}=\frac{0.1087g}{0.1153g}\times 100=94.27\%

  • <u>For Hydrogen:</u>

Mass of sample = 0.1153 g

Mass of hydrogen = 0.0066 g

Putting values in equation 1, we get:

\%\text{ composition of hydrogen}=\frac{0.0066g}{0.1153g}\times 100=5.72\%

Hence, the mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

8 0
2 years ago
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