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Leviafan [203]
1 year ago
15

Compare the composition of sucrose purified from the sugar cane with the composition of sucrose purified from sugar beets.

Chemistry
2 answers:
Eva8 [605]1 year ago
8 0
The problem ask to compare the composition of sucrose purified from the sugar cane with the composition of sucrose purified from beets and the answer is that the two sucrose molecule will be chemically and structurally the same. I hope you are satisfied with my answer and feel free to ask for more 
Vladimir79 [104]1 year ago
3 0

Answer: they are the same.


Explanation:


1) Sucrose is a compound with chemical formula C₁₂H₂₂O₁₁


2) That means that all molcules of sucrose will have the same kind of atoms in the same proportion, whic is to say same composition:


12 atoms of C: 22 atoms of H: 11 atoms of O, per each molecule of sucrose.


3) For this question you can rely in the definition of compound: a pure substance formed by the combination of two or more elements always in the same ratio (same composition).


4) That also implies, that all the molecules of sucrose have the same properties.

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Calculate the mass of 3.75 x 10^23 molecules of CaSO4 Please HelpIn a hurry Ill give brainliest
SOVA2 [1]

Answer:

Mass = 84.82 g

Explanation:

Given data:

Number of molecules of CaSO₄ = 3.75× 10²³

Mass in gram = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

3.75× 10²³ molecule × 1 mol / 6.022 × 10²³ molecules

0.623 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.623 mol × 136.14 g/mol

Mass = 84.82 g

7 0
1 year ago
Part 1: Name the type of chemical reaction that occurs when magnesium chloride solution (MgCl2) reacts with sodium carbonate sol
garri49 [273]

Answer:

Mg would blow off. AI would be affective to copper but not to MG

Explanation:

7 0
1 year ago
A 7.50 liter sealed jar at 18 °c contains 0.125 moles of oxygen and 0.125 moles of nitrogen gas. what is the pressure in the con
devlian [24]
The ideal gas equation is;
PV = nRT; therefore making P the subject we get;
P = nRT/V
The total number of moles is 0.125 + 0.125 = 0.250 moles 
Temperature in kelvin = 273.15 + 18 = 291.15 K
PV = nRT
P = (0.250 × 0.0821 )× 291.15 K ÷ (7.50 L) = 0.796 atm
Thus, the pressure in the container will be 0.796 atm
4 0
1 year ago
Read 2 more answers
The chemical equation, Cr + Fe(NO3)2 → Fe + Cr(NO3)3, is an example of which type of reaction?
Angelina_Jolie [31]

Answer:

Redox type

Explanation:

The reaction is:

2Cr +  3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃

2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.

If we see oxidation state, we see that chromium changes from 0 to +3

Iron changed the oxidation state from +2 to 0

Remember that elements at ground state has 0, as oxidation state.

Iron is being reduced while chromium is oxidized. Then, the half reactions are:

Fe²⁺  +  2e⁻ ⇄  Fe    (Reduction)

Cr ⇄ Cr³⁺  +  3e⁻    (Oxidation)

When an element is being  reduced, while another is being oxidized, we are in prescence of a redox reaction.

8 0
2 years ago
What is the concentration of Iodine I2 molecules in a solution containing 2.54 g of iodine 250 cm3 of solution? A 0.01mol/dm3 B
gulaghasi [49]

Answer:

C. 0.04 moles per cubic decimeter.

Explanation:

The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine (c), measured in moles per cubic decimeter, can be determined by the following formula:

c = \frac{m}{M\cdot V} (1)

Where:

m - Mass of iodine, measured in grams.

M - Molar mass of iodine, measured in grams per mol.

V - Volume of solution, measured in cubic decimeters.

If we know that m = 2.54\,g, M = 253.809\,\frac{g}{mol} and V = 0.25\,dm^{3}, then the concentration of iodine in a solution is:

c = \frac{2.54\,g}{\left(253.809\,\frac{g}{mol} \right)\cdot (0.25\,dm^{3})}

c = 0.04\,\frac{mol}{dm^{3}}

Hence, the correct answer is C.

3 0
2 years ago
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