Assuming that the change of volumen was done at constant pressure and the quantity of gas did not change, you use Charles' Law of gases, which is valid for ideal gases:
V / T = constant => V1 / T1 = V2 / T2 => V1 = [V2 / T2] * T1.
Now plug in the numbers ,where T1 and T2 have to be in absolute scale.
T1 = 38.1 + 273.15 K = 311.25K
T2 = 15.0 + 273.15 K = 288.15K
V1 = 4.5L * 311.25K / 288.15 K = 4.86L.
Answer: 4.86
Answer:
The energy released in the decay process = 18.63 keV
Explanation:
To solve this question, we have to calculate the binding energy of each isotope and then take the difference.
The mass of Tritium = 3.016049 amu.
So,the binding energy of Tritium = 3.016049 *931.494 MeV
= 2809.43155 MeV.
The mass of Helium 3 = 3.016029 amu.
So, the binding energy of Helium 3 = 3.016029 * 931.494 MeV
= 2809.41292 MeV.
The difference between the binding energy of Tritium and the binding energy of Helium is: 32809.43155 - 2809.412 = 0.01863 MeV
1 MeV = 1000keV.
Thus, 0.01863 MeV = 0.01863*1000keV = 18.63 keV.
So, the energy released in the decay process = 18.63 keV.
The force that holds protons and neutrons together is too strong to overcome.
<h3>Explanation</h3>
Consider the location of the particles in an atom.
- Electrons are found outside the nucleus.
- Protons and neutrons are found within the nucleus.
Protons carry positive charges and repel each other. The nucleus will break apart without the strong force that holds the protons and neutrons together. This force is much stronger than the attraction between the nucleus and the electrons. X-rays are energetic enough for removing electrons from an atom. However, you'll need a collider to remove protons from a stable nucleus. You could well have ionized the atom with all that energy.
Also, changing the number of protons per nucleus will convert the halogen atom to an atom of a different element. Rather than making the halogen negative, removing a proton will convert the halogen atom to the negative ion of a different element.
Answer:
dispersion forces
Explanation:
SO3 is a trigonal planar molecule. All the dipoles of the S-O bonds cancel out making the molecule to be a nonpolar molecule.
The primary intermolecular force in nonpolar molecules is the London dispersion forces. As expected, the London dispersion forces is the intermolecular force present in SO3.
Hence SO3 is a symmetrical molecule having only weak dispersion forces acting between its molecules.
