A branched alkane has HIGHER boiling point relative to the isomeric linear alkane. There are STRONGER london force interactions in the branched alkane.
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Answer:
The answer to your question is P = 2.13 atm
Explanation:
Data
Pressure = ?
number of moles = 3.54
Temperature = 376 °K
Volume = 51.2 L
R = 0.08205 atm L/mol°K
Formula
PV = nRT
- Solve for P
P = nRT / V
- Substitution
P = (3.54)(0.08205)(376) / 51.2
- Simplification
P = 109.21 / 51.2
Result
P = 2.13 atm
Answer:
1210 grams
Explanation:
Message me for extra info.
snap- parkguy786
0.53 x 200ml = 106 ml of the pH 9.0 buffer + 94 ml of the pH 10 buffer gives the desired solution
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Answer would be B. I provided work on an image attached. Message me if u have any other questions on how to do it