Answer;
= 18.24
Explanation;
The ratio of N and O in the formula NO2 IS 1:2
Mass of nitrogen gas is 0.500 g
Moles of nitrogen will be;
= 0.500/16 = 0.03125 moles
Therefore;
The moles of Oxygen from the ratio will be;
= 0.03125 × 2 = 0.0625 moles
But; 0.0625 moles is equal to 1.140 g of Oxygen
The atomic number (mass in 1 mole) will be;
= 1.140 /0.0625
= 18.24
Thus the atomic number of Oxygen from the data is 18.24
I believe the correct answer true. According to the law of conservation of mass, in a chemical reaction the total starting mass of all the reactants equals the total final mass of all the products. This law states that mass cannot be created or be destroyed. So, the total mass that goes in a process should be equal to the mass that goes out the process. This is true for chemical reactions and physical processes. It is Antoine Lavoisier who described this and is a basic principle used in physics and in chemistry. Mass, unlike energy, cannot be transformed to any form so however the transformation happens the mass should be constant.
Answer is "B - 700,000".<span>
<span>Kinetic energy of a single particle (atom or molecule)<span> is directly proportional to its
temperature according to the following equation.</span></span>
KE = (3kT)/2
<span>Where </span>KE<span> is the
kinetic energy of a single atom/molecule (</span>J<span>), </span>k<span> is the Boltzmann
constant (</span>1.381 × 10</span>⁻²³ J/K<span>) and </span>T<span> is the temperature (</span>K<span>) </span><span>
When temperature increases, then the kinetic
energy increases.
<span>If kinetic
energy of atoms increases, then there will be more motions which create many
collisions.</span></span>
For the first task, lighting a campfire can be used. Quantities of firestarter and kindling do not need to be precise. For the second task, the process of titration can be used. In a titration, the precise amount of a substance may be determined by adding a precise amount of a reactive species
Answer:
MnO- Manganese Oxide
Explanation:
Empirical formula: This is the formula that shows the ratio of elements
present in a
compound.
How to determine Empirical formula
1. First arrange the symbols of the elements present in the compound
alphabetically to determine the real empirical formula. Although, there
are exceptions to this rule, E.g H2So4
2. Divide the percentage composition by the mass number.
3. Then divide through by the smallest number.
4. The resulting answer is the ratio attached to the elements present in
a compound.
Mn O
% composition 72.1 27.9
Divide by mass number 54.94 16
1.31 1.74
Divide by the smallest number 1.31 1.31
1 1.3
The resulting ratio is 1:1
Hence the Empirical formula is MnO, Manganese oxide
