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jarptica [38.1K]
2 years ago
10

According to the equation below, how many moles of Ca(OH)2 are required to react with 1.36 mol H3PO4 to produce Ca3(PO4)2? 3Ca(O

H)2+2H3PO4⟶Ca3(PO4)2+6H2O
Chemistry
1 answer:
allsm [11]2 years ago
3 0

<u>Answer:</u> The amount of calcium hydroxide needed to react is 2.04 moles

<u>Explanation:</u>

We are given:

Moles of phosphoric acid = 1.36 moles

For the given chemical equation:

3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O

By Stoichiometry of the reaction:

2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide

So, 1.36 moles of phosphoric acid will react with = \frac{3}{2}\times 1.36=2.04mol of calcium hydroxide

Hence, the amount of calcium hydroxide needed to react is 2.04 moles

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Draw an acceptable lewis structure for the molecular ion (radical cation) formed from this molecule when it is bombarded by high
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<span>To draw an acceptable lewis structure we must first determine the number of valance elections of the molecule in the ground state, and then adjust the molecule to refect the molecular radial cation after one or more of the electrons have been removed from its outter most shell. The lewis structure should refect the best configuation with good resonance and stability.</span>
3 0
2 years ago
For nitrogen gas the values of Cv and Cp at 25°C are 20.8 J K−1 mol−1 and 29.1 J K−1 mol−1, respectively. When a sample of nitro
kifflom [539]

Answer:

The fraction of energy used to  increase the internal energy of the gas is 0.715

Explanation:

Step 1: Data given

Cv for nitrogen gas = 20.8 J/K*mol

Cp for nitrogen gas = 29.1 J/K*mol

Step 2:

At a constant volume, all the  heat will increase the internal energy of the gas.

At constant pressure, the gas expands and does work., if the volume changes.

Cp= Cv + R

⇒The value needed to change the internal energy is shown by Cv

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To find what fraction of the energy is used to increase the internal energy of the gas, we have to calculate the value of Cv/Cp

Cv/Cp = 20.8 J/K*mol / 29.1 J/K*mol

Cv/Cp = 0.715

The fraction of energy used to  increase the internal energy of the gas is 0.715

3 0
1 year ago
Read 2 more answers
What is the mass in grams of 6.022×1023 atoms of mass 16.00 amu?
german
16.00 g -------------- 6.02x10²³ atoms
?? g ----------------- 6.022x10²³ atoms

16.00 x (6.022x10²³) / 6.02x10²³ =

=> 16 g


7 0
1 year ago
What is the mass in grams of 7.5 x 10^15 atoms of nickel?
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Atomic mass Ni = 58.69 a.m.u

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?? g --------------------- 7.5x10¹⁵ atoms

58.69x (7.5x10¹⁵) / 6.02x10²³

=> 7.31x10⁻⁷ g
6 0
2 years ago
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a radiator is filled with a mixture of 3.25kg ethylene glycol (C2H6O2) in 7.75kg of water. calculate the molality of this questi
Vladimir [108]
3.25 kg in g = 3.25 * 1000 = 3250 g

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Number of moles:

n = mass solute / molar mass

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M = 52.419 / 7.75

M = 6.7637 mol/kg

hope this helps!
5 0
2 years ago
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