According to the equation below, how many moles of Ca(OH)2 are required to react with 1.36 mol H3PO4 to produce Ca3(PO4)2? 3Ca(O
1 answer:
<u>Answer:</u> The amount of calcium hydroxide needed to react is 2.04 moles
<u>Explanation:</u>
We are given:
Moles of phosphoric acid = 1.36 moles
For the given chemical equation:
By Stoichiometry of the reaction:
2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide
So, 1.36 moles of phosphoric acid will react with = of calcium hydroxide
Hence, the amount of calcium hydroxide needed to react is 2.04 moles
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Explanation:
An image of the compound as obtained from chemlibretext is attached to this answer.
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Answer:
a) 11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.
15.4 moles of water are formed from 3.85 mole of propane.
b)0.5176 moles of water are formed from 0.647 mole of oxygen gas.
0.1294 moles of propane are consumed.
Explanation:
a) Moles of propane = 3.85 moles
According to reaction, 1 mole of propane gives 3 moles of carbon dioxide gas.
Then 3.85 moles of propane will give:
of carbon dioxide gas.
11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.
According to reaction, 1 mole of propane gives 4 moles of water gas.
Then 3.85 moles of propane will give:
of water .
15.4 moles of water are formed from 3.85 mole of propane.
b) Moles of oxygen gas = 0.647 moles
According to reaction, 5 mole of oxygen gas gives 4 moles of water.
Then 0.647 moles of oxygen will give:
of water.
0.5176 moles of water are formed from 0.647 mole of oxygen gas.
According to reaction, 5 mole of oxygen gas reacts with 1 mole of propane.
Then 0.647 moles of oxygen will give:
of propane.
0.1294 moles of propane are consumed.