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Amanda [17]
2 years ago
13

In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form

ed during the reaction. A cross drawn at the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial record of the experiment is shown. Experimental Record Flask Volume of HCl Volume of Sodium Thiosulfate Volume of Water Time 1 10 mL 10 mL 40 mL 14 seconds 2 10 mL 20 mL 30 mL 3 10 mL 30 mL 20 mL 4 10 mL 40 mL 10 mL Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete sentences to explain the trend you predicted. You do not have to determine exact values for time; just describe the trend you would expect (increase or decrease) and why it occurs.
Chemistry
1 answer:
erastovalidia [21]2 years ago
5 0

Answer:

The time taken for the cross mark to disappear decreases steadily down the column.

Explanation:

Now if we look at the data provided, we will discover that the volume of the HCl was held constant while the volume of the thiosulphate was increased steadily and the volume of water decreased steadily.

Recall that a system is more concentrated when it contains less volume of water and more volume of reactants. Hence as the volume of water in the system is being reduced, the concentration of reactants is increased.

It has been established that an increase in the concentration of reactants lead to an increase in the rate of reaction. The disappearance of the cross shows the completion of the reaction between HCl and thiosulphate. The faster or slower the cross disappears, the faster or slower the rate of reaction.

Since increase in concentration of reactants increases the rate of reaction, it is observed that as the volume of the thiosulphate increases (reactant concentration increases) the cross disappears faster (rate of reactant increases). Hence as the volume of thiosulphate increases, it takes a shorter time for the cross to disappear. This implies that the time column in the table (refer to the question) will decrease steadily as the volume of thiosulphate increases.

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Nitrogen gas can be prepared by passing gaseous ammonia over solid copper (II) oxide at high temperatures. If 18.1 g of Nh3 is r
Scilla [17]

I first converted the given grams of the reactants into moles, and then divided the moles by the coefficients in front of each of the reactant. The result with the smallest value will be the limiting reactant, and the value of CuO was the smallest, so it's the limiting reactant.

After figuring out which reactant is the limiting one, I took their given grams and converted it into moles, the divided it by the ratio of N2 to CuO (it's in the equation) to obtain the moles of N2, and then multiply it with the molar mass of N2 to get its mass in grams.

6 0
2 years ago
Lars observes a substance to be a solid and to float in water at room temperature (23°C). Based on the given properties, which s
Triss [41]

Answer:

D. Sulfur Hexafluride

Explanation:

  • above it says the substance floats above water at room temperature and lists some substances and their density at room temp!
  • we know that the density of water is 1.0 so the substance in order for it to float has to be less than 1.0 and the densities for Sulfer Hexa, are all less than 1!!

I hope this helped !!

4 0
2 years ago
What is the mole fraction of potassium dichromate, K2Cr2O7, in a solution prepared from 24.42 g of potassium dichromate and 240.
Harrizon [31]

Answer:

6.19\times 10^{-3} is the mole fraction of potassium dichromate.

Explanation:

Mass of potassium dichromate = 24.42 g

Moles of  potassium dichromate =n_1=\frac{24.42 g}{294.185 g/mol}=0.0830 mol

Mass of water = 240.0 g

Moles of water =n_2=\frac{240.0 g}{18.015 g/mol}=13.3222 mol

Mole fraction is calculated by:

\chi_1=\frac{n_1}{n_1+n_2}

\chi_1=\frac{0.0830 mol}{0.0830 mol+13.3222 mol}=0.00619=6.19\times 10^{-3}

6.19\times 10^{-3} is the mole fraction of potassium dichromate.

8 0
2 years ago
Determine the transition length at the entrance to a 10 mm tube through which 100 percent glycerol at 60 C is flowing at a veloc
Readme [11.4K]

Answer: Option (d) is the correct answer.

Explanation:

The given data is as follows.

Tube diameter d = 10 mm = 0.01 m

Velocity of glycerol, v = 0.5 m/s

Density of glycerol (\rho) = 1240 kg/m3

Dynamic viscosity of glycerol (\mu) = 0.0813 pa.s

Reynolds number (Re) = \rho \times velocity \times \frac{density}{\mu}

                                     = 1240 \times 0.5 \times \frac{0.01}{0.0813}

                                     = 76.26

Therefore, according to Reynolds number we can say that flow is laminar.

                     Lt = 0.05 \times Re \times d

                         = 0.05 \times 76.26 \times 0.01

                         = 0.03813 m

As it is known that 1 m = 1000 mm. Hence, in 0.03813 m will be equal to 0.03813 m \times \frac{1000 mm}{1 m}

                         = 38.13 mm

Thus, we can conclude that the transition length of glycerol is 38.13 mm.

5 0
2 years ago
Fluorine gas is placed in contact with calcium metal at high temperatures to produce calcium fluoride powder. What is the formul
Mars2501 [29]

Answer:

Upper F subscript 2 (g) plus upper C a (s) right arrow with delta above upper C a upper F subscript 2 (s).

Explanation:

This is a chemical reaction problem.

In expressing any chemical reaction, we need to understand that there are reactants and products.

  • The reactants are the species on the left hand side that are combining.
  • The products are the species on the right hand side that are formed.
  • Every chemical reaction is obeys the law of conservation of matter i.e equal number of matter on both sides.

Using the statement of this problem, we can deduce that;

 Reactants are Fluorine gas and Calcium metal

  Product is Calcium Fluoride

Note: A metal is a solid(s) and powder is a solid(s). A gas is denoted as (g). They depict the state of the species reacting.

                    F₂_{(g)}     +    Ca_{(s)}               →           CaF₂_{(s)}

We can see that equal number of atoms are on both sides of the expression.

7 0
2 years ago
Read 2 more answers
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