I first converted the given grams of the reactants into moles, and then divided the moles by the coefficients in front of each of the reactant. The result with the smallest value will be the limiting reactant, and the value of CuO was the smallest, so it's the limiting reactant.
After figuring out which reactant is the limiting one, I took their given grams and converted it into moles, the divided it by the ratio of N2 to CuO (it's in the equation) to obtain the moles of N2, and then multiply it with the molar mass of N2 to get its mass in grams.
Answer:
is the mole fraction of potassium dichromate.
Explanation:
Mass of potassium dichromate = 24.42 g
Moles of potassium dichromate =
Mass of water = 240.0 g
Moles of water =
Mole fraction is calculated by:


is the mole fraction of potassium dichromate.
Answer: Option (d) is the correct answer.
Explanation:
The given data is as follows.
Tube diameter d = 10 mm = 0.01 m
Velocity of glycerol, v = 0.5 m/s
Density of glycerol (
) = 1240 kg/m3
Dynamic viscosity of glycerol (
) = 0.0813 pa.s
Reynolds number (Re) =
=
= 76.26
Therefore, according to Reynolds number we can say that flow is laminar.
Lt =
=
=
As it is known that 1 m = 1000 mm. Hence, in 0.03813 m will be equal to 
= 38.13 mm
Thus, we can conclude that the transition length of glycerol is 38.13 mm.
Answer:
Upper F subscript 2 (g) plus upper C a (s) right arrow with delta above upper C a upper F subscript 2 (s).
Explanation:
This is a chemical reaction problem.
In expressing any chemical reaction, we need to understand that there are reactants and products.
- The reactants are the species on the left hand side that are combining.
- The products are the species on the right hand side that are formed.
- Every chemical reaction is obeys the law of conservation of matter i.e equal number of matter on both sides.
Using the statement of this problem, we can deduce that;
Reactants are Fluorine gas and Calcium metal
Product is Calcium Fluoride
Note: A metal is a solid(s) and powder is a solid(s). A gas is denoted as (g). They depict the state of the species reacting.
F₂
+ Ca
→ CaF₂
We can see that equal number of atoms are on both sides of the expression.