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timurjin [86]
2 years ago
6

How many moles of nitrogen are in 3.7 moles of C8H11NO2?

Chemistry
1 answer:
Phoenix [80]2 years ago
4 0
<h3>Answer:</h3>

               3.7 Moles of Nitrogen

<h3>Explanation:</h3>

                      On observing the chemical formula C₈H₁₁NO₂ (might be formula of Dopamine) it is found that one mole of this compound contains;

8 Moles of Carbon

11 Moles of hydrogen

1 Mole of Nitrogen and

2 Moles of Oxygen respectively.

<u>Calculate Number of Moles of Nitrogen:</u>

As,

                   1 Mole of C₈H₁₁NO₂ contains  =  1 Mole of Nitrogen

So,

            3.7 Moles of C₈H₁₁NO₂ will contain  =  X Moles of Nitrogen

Solving for X,

                       X  =  (3.7 Moles × 1 Mole) ÷ 1 Mole

                       X  =  3.7 Moles of Nitrogen

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tatuchka [14]

Answer:

3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3

Explanation:

8 0
2 years ago
Predict the initial and isolated products for the reaction. The starting material is a 6 carbon chain where there is a triple bo
satela [25.4K]

Answer:

See explanation and image attached

Explanation:

This reaction is known as mercuric ion catalyzed hydration of alkynes.

The first step in the reaction is attack of the mercuric ion on the carbon-carbon triple bond, a bridged intermediate is formed. This bridged intermediate is attacked by water molecule to give an organomercury enol. This undergoes keto-enol tautomerism, proton transfer to the keto group yields an oxonium ion, loss of the mercuric ion now gives equilibrium keto and enol forms of the compound. The keto form is favoured over the enol form.

7 0
2 years ago
At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same condition
yan [13]

Answer:

44Kj

Explanation:

These are the equations for the reaction described in the question,

Vaporization which can be defined as transition of substance from liquid phase to vapor

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-241.8kj -------eqn(1)

H2(g)+ 1/2 O2(g) ------>H2O(l).

Δ H =285.8kj ---------eqn(2)

But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as

H2O(l) ------>>H2O(g)---------------eqn(3)

But the equation from eqn(2) the eqn does go with vaporization so we can re- write as

H2O ------> H2(g)+ 1/2 O2(g)

Δ H= 285.8kj ---------------eqn(4)

To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)

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5 0
2 years ago
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kenny6666 [7]

Answer:

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I got it right on the quiz. This is what I saw. Read this, "Adding water to an acid or base will change its pH. Water is mostly water molecules so adding water to an acid or base reduces the concentration of ions in the solution. When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7."

Hope this helps! Tell me if this is wrong just incase.

8 0
2 years ago
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