Answer:

Explanation:
Hello,
In this case, for each nitrate-based salt, we compute the nitrate moles as shown below:



We notice calcium nitrate has two moles of nitrate ion, sodium nitrate has one and aluminium nitrate has three. Hence we add the moles to obtain the total moles nitrate ion:

Finally, we compute the molarity:

Regards.
The alcohol being oxidized must not be a tertiary alcohol.
A tertiary alcohol is one in which the -OH group is attached to a carbon atom which is attached to three other carbon atoms. This "closes off" the alcohol group and prevents the formation of oxidation products. This is the reason why tertiary alcohols do not undergo oxidation in mild conditions.
The answer is A, i'm also on study island on this test. It has a star next to it. So yep we're right!
Answer: The new temperature is 10643 K
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 750.0 mm Hg = 0.98 atm (760mmHg=1atm)
= final pressure of gas = 3.50 atm
= initial volume of gas = 2.00 L
= final volume of gas = 20.0 L
= initial temperature of gas = 
= final temperature of gas = ?
Now put all the given values in the above equation, we get:


Thus the new temperature is 10643 K
Answer:
Molecular formula of the compound = H₂CO₃
Explanation:
First, the empirical formula of the compound is determined
Percentage by mass of each element is given as shown below:
H = 3.3% ; C = 19.9%; O = 77.4%
Mole ratio of the elements= percentage mass/ molar mass
H = 3.3/ 1 = 3.3
C = 19.3/12 = 1.6
O = 77.4/16 = 4.8
whole number ratio is obtained by dividing through with the smallest ratio
H = 3.3/1.6; C = 1.6/1.6; O = 4.8/1.6
H : C : O = 2 : 1 : 3
Empirical formula = H₂CO₃
Molecular formula/mass = n(empirical formula/mass)
60 = n(2*1 + 12*1 + 16*3)
60 = n(62)
n = 60/62 = 0.96
n is approximately = 1
Therefore, molecular formula of the compound = (H₂CO₃) * 1
Molecular formula of the compound = H₂CO₃