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morpeh [17]
2 years ago
13

The standard heats of combustion (δh∘) per mole of 1,3-butadiene, c4h6(g); butane, c4h10(g); and h2(g) are −2540.2,−2877.6, and

−285.8kj, respectively. Use these data to calculate the heat of hydrogenation of 1,3-butadiene to butane. C4h6(g)+2h2(g)→c4h10(g)
Chemistry
1 answer:
ryzh [129]2 years ago
5 0

solution:

Hydration is the addition of water; hydrogenation is the addition of hydrogen.  

desire rxn: _C4H6(g) + 2 H2(g)-----> C4H10(g)___dHhy = ??  

knowns:  

__________C4H6 + 11/2 O2 --------> 4CO2 + 3H2O______dHox = -2540.2 kJ/mole  

__________4CO2 + 5H2O -----------> C4H10 + 13/2 O2___-dHox = 2877.6 kJ/mole  

___________2(1/2 O2 + H2 -------------> H2O)___________2*dHox = 2(-285.8 kJ/mole)  

Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem


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2. Suggest four ways in which the concentration of PH3 could be increased in an equilibrium described by the following equation:
Nesterboy [21]

Answer

  • increase in temperature
  • decrease in pressure
  • continuous removal of PH3
  • adding more of P into the system

Explanation:

        In the reaction   P4(g)+6H2(g) ⇌ 4PH3(g);

  • The effect of temperature on equilibrium has to do with the heat of reaction. Recall that for an endothermic reaction, heat is absorbed in the reaction, and the value of ΔH is positive. Thus, for an endothermic reaction, we can picture heat as being a reactant:

        heat+A⇌BΔH=+

  • Since the reaction is endothermic reaction, heat is a absorbed. Decreasing the temperature will shift the equilibrium to the left, while increasing the temperature will shift the equilibrium to the right forming more of PH3.
  • According to Le Chatelier’s principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. In the same Way, reducing the concentration of the product will also shift equilibrium to the right continually forming PH3 as it is removed.

4 0
1 year ago
Anna lives in a city that experiences high precipitation, with an average annual rainfall of 524 millimeters. It is warm all yea
gavmur [86]

Anna lives in a city that is part of the tropical climate types. It has a constantly warm weather, and thus higher humidity, and according to the annual rainfall, it is most probably a rainfall that appears seasonally, not throughout the whole year.

Tim, on the other hand, lives in a city that is part of the dry climate types. It is most probably a place that is deep into the mainland, like the cold deserts of Central Asia, where the temperatures in the summer are high, and in winter are very low. Because of the distance from the sea, the rainfall doesn't reach this places, so they are very dry, and only have symbolic amount of annual rainfall.

6 0
2 years ago
Iodine is 80% 127I, 17% 126I, and 3% 128I. Calculate the average atomic mass of Iodine.
trasher [3.6K]
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>

Given

80% 127I, 17% 126I, and 3% 128I.

Required

The average atomic mass

Solution

The elements in nature have several types of isotopes

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%

Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128

Atomic mass of Iodine = 101.6 + 21.42 + 3.84

Atomic mass of Iodine = 126.86 amu

6 0
2 years ago
Which contributes to the dissolution of sugar in water?
AURORKA [14]

Option C: The dissociation of a polar covalent compound in water.

Sugar is made up of sucrose molecules containing polar covalent bonds. They have same type of oxygen-hydrogen covalent bonds that are present in water.

Since, sugar is not an ionic compound, option a and option b are incorrect. Also, due to same type of bonding in water and sugar molecules there will be no such force of attraction between them, this will opt out the option d.

Thus, dissolution of sugar in water is the dissociation of a polar covalent compound in water and option c is correct.

7 0
2 years ago
Read 2 more answers
Britta traveled 1250 km on her road trip and used 209 L of gasoline, filling her tank atan average of 1.14 euros per liter. Pier
icang [17]

Answer:

  • Britta paid more per kilometer driven

Explanation:

<u>1) Britta:</u>

  • Distance traveled: 1,250 Km
  • Gasoline used: 209 liter
  • Gasoline price: 1.23 euros / liter

Cost per km = total cost of gasoline / distance traveled

Cost per km = gasoline used × gasoline price / distance traveled

Cost per km = 209 liter × 1.14 (euro / liter) / 1,250 km =  0.19 euro / km

<u>2) Pierce:</u>

  • Distance traveled: 1,405 km
  • Gasoline used: 175 liter
  • Gasoline price = 1.23 euros / liter

Cost per km = 175 liter × 1.23 (euro / liter) / 1,405 km =  0.15 euro / km

<u>3) Comparison:</u>

  • 0.19 > 0.15 ⇒ Britta paid more per kilometer driven
4 0
2 years ago
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