The protons in an nucleus of an atom will not change unless a nuclear reaction takes place. The number of protons is equal to the atomic number of the element. For a neutral atom, the number of electrons and protons are equal. When they are unequal, then the atom occurs as an ion. It will has a net charge with it. The ion O²⁻ has a net charge of negative positive 2 because it has 2 more electrons than its protons. Since neutral oxygen has 8 protons, then O²⁻ ion has 8 protons and 10 electrons.
Here, the three different notation of the p-orbital in different sub-level have to generate
The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number 
depends upon the value of l, which are -l to +l.
Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as 
, 
and 
in space.
The three p-orbital can be distinguish by the quantum numbers as-
For 2p orbitals (principal quantum number is 2)
1) n = 2, l = 1, m = -1
2) n = 2, l = 1, m = 0
3) n = 2, l = 1, m = +1
Thus the notation of different p-orbitals in the sub level are determined.
Answer:
P = 17.9618 atm
Explanation:
The osmotic pressure can be calculated and treated as if we are talking about an ideal gas, and it's expression is the same:
pV = nRT
However the difference, is that instead of using moles, it use concentration so:
p = nRT/V ----> but M = n/V so
p = MRT
We have the temperature of 18 °C (K = 18+273.15 = 291.15 K) the value of R = 0.08206 L atm / K mol, so we need to calculate the concentration, and we have the mass of HCl, so we use the molar mass of HCl which is 36.45 g/mol:
n = 13.7/36.45 = 0.3759 moles
M = 0.3759/0.5 = 0.7518 M
Now that we have the concentration, let's solve for the osmotic pressure:
p = 0.7518 * 0.08206 * 291.15
<em><u>p = 17.9618 atm</u></em>
Answer:
82.9 mL
Explanation:
1. Volume of silver
2. Volume of gold
3. Total volume of silver and gold
V = 4.766 mL + 2.591 mL = 7.36 mL
4 New reading of water level
V = 75.5 mL + 7.36 mL = 82.9 mL
Answer:
Drug calculation
If we have 45g of clobetasol = 0.05%w/w
Then what mass in g of clobetasol is in 0.03%w/w = 45 x 0.03/0.05 =27g
It means that 27g of clobetasol must be added to change the drug strength to 0.03% w/w
