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worty [1.4K]
2 years ago
8

Given that the ionizable h atoms are associated with carboxyl groups, draw a plausible structure for maleic acid. draw the molec

ule by placing atoms on the grid and connecting them with bonds. include all lone pairs of electrons.

Chemistry
2 answers:
NeTakaya2 years ago
7 0
The structure of maleic acid and its ionized form :

Illusion [34]2 years ago
4 0

Answer:

HOOCCH=CHCOOH

Explanation:

Hello,

Maleic acid is a butenedioic acid in which the double bond has cis- (Z)-configuration. It has a role as a plant metabolite, an algal metabolite and a mouse metabolite. On the attached document, you will the see maleic acid's structure by showing its lone electrons in order to accomplish the octates for both carbons and oxygens.

Best regards.

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Consider the formation of nitryl fluoride: 2NO2(g)+F2(g)⇌2NO2F(g) The reaction is first order in F2 and second order overall. Wh
Dahasolnce [82]

Answer:

Rate = k[NO_{2}][F_{2}]

Explanation:

  • Two reactants are present in this reaction which are NO_{2}and F_{2}
  • We know overall order of a reaction is summation of individual order with respect to reactants present in rate law equation.
  • Here, overall order of reaction is 2 including first order with respect to F_{2}
  • So, rate of reaction should also be first order with respect to another reactant i.e. first order with respect to NO_{2}
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2 years ago
Is the aqueous solution of each of these salts acidic, basic, or neutral? (a) cr(no3)3 acidic basic neutral (b) nahs acidic basi
melisa1 [442]
1) chromium(III) nitrate is acidic,  because it is the salt of weak base (chromium(III) hydroxide Cr(OH)₃) and strong acid (nitric acid HNO₃).
2) sodium hydrosulfide is basic, because it is the salt of strong base (sodium hydroxide MaOH) and weak acid (hydrogen sulfide H₂S).
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5 0
2 years ago
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A quantity of 85.0 mL of 0.900 M HCl is mixed with 85.0 mL of 0.900 M KOH in a constantpressure calorimeter that has a heat capa
bogdanovich [222]

Explanation:

The given data is as follows.

         V_{1} = 85.0 ml,        M_{1} = 0.9 M

         V_{2} = 85.0 ml,        M_{1} = 0.9 M

Hence, number of moles of HCl and KOH will be the same because both the solutions have same volume and molarity.

So,     No. of moles = Molarity × Volume

                                = 0.9 M \times 0.085 L        (as 1 L = 1000 ml so, 85 ml = 0.085 L)

                                = 0.076 mol

As 1 mole gives 56.2 kJ/mol of heat of neutralization. Hence, calculate the heat of neutralization given by 0.076 moles as follows.

              56.2 kJ/mol \times 0.076 mol

                    = 4.271 kJ

or,                 = 4271 J     (as 1 kJ = 1000 J)

Therefore,    heat released = - heat of gained by calorimeter

Since, it is given that density of the solution is similar to the density of water which is 1 g/ml.

Hence,     mass of HCl = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Similarly,    mass of KOH = = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Hence, total mass of the solution = 85 g + 85 g

                                                        = 170 g

Also,                   q = mC \Delta T

                     4271 J = 170 g \times 325 J/^{o}C \times (T_{f} - 18.24)^{o}C    

                     0.0773 = T_{f} - 18.24

                    T_{f} = 18.317^{o}C  

Thus, we can conclude that final temperature of the mixed solution is 18.317^{o}C.

6 0
2 years ago
Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3
Helen [10]
Equilibrium equation is

<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>

<span>From the reaction equation above, the formula for Ksp: </span>

<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know  [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
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2 years ago
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They are given by the following conversion factors:

carbohydrates = 4 kcal/g
protein = 4 kcal/g
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If the slice of pizza contains 29 g carbohydrates, that means there are 4 kcal/g × 29 g = 116 kcal from carbohydrates. It contains 13 g protein, so there are 4 kcal/g <span>× 13 g = 52 kcal from protein.

The total number of kilocalories is 280, of which we have accounted for 168 (116+52). 280–168=112 kcal.

So, there are 112 kcal from fat. Using our conversion factor, 112 kcal </span><span>× 1 g/9 kcal = 12 g fat.</span>
3 0
2 years ago
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