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katrin2010 [14]
2 years ago
7

An unknown gas effuses at a rate 0.797 times that of nitrogen at the same temperature. what is the molar mass of the unknown gas

?
Chemistry
2 answers:
kicyunya [14]2 years ago
7 0
<span>mass B/molar mass A = (rate A/rate B)^2. we know our unknown gas (A) effuses at .797 times our known gas (B) so rate A/rate B = .797 so 0.797^2 = 28 / molar mass A Molar mass A = 28 / 0.635 = 44.09 g / mole Molar mass is 44.09 g/mol</span>
kramer2 years ago
5 0

Answer: Molar mass of unknown gas=43.75gmol^{-1}

Explanation: Graham's Law states that the rate of effusion of gas is inversely proportional to the square root of their atomic masses.

{\text {Rate of effusion}}=\frac{1}{\sqrt\text {Molecular mass}}

\frac{R_1}{R_2}=\sqrt\frac{M_2}{M_1}

R_1= rate of effusion of nitrogen = x

R_2= rate of effusion of unknown gas = 0.797x

M_1= Molecular mass of nitrogen(N_2) = 28g

M_2= Molecular mass of unknown gas

\frac{x}{0.797x}=\sqrt\frac{M_2}{28gmol^{-1}}

M_2=43.75gmol^{-1}


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2 years ago
A 500.0 ml buffer solution is 0.10 m in benzoic acid and 0.10 m in sodium benzoate and has an initial ph of 4.19. part a what is
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4.29
8 0
2 years ago
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2 years ago
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3 0
2 years ago
Simple chem question - please help!
sveta [45]
Molar mass O₂ = 32.0 g/mol and N₂ = 28.0 g/mol

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7 g ----------> ?

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Mass of O₂ = 448 / 28.0

= 16 g of O₂

Answer B

hope this helps!
7 0
2 years ago
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