Question

7.47 Two atoms have the electron configurations 1s22s22p6 and 1s22s22p63s1. The first ionization energy of one is 2080 kJ/mol and that of the other is 496 kJ/mol. Match each ionization energy with one of the given electron configurations.

Answer 1

Answer:

2080 kJ/mol is the first ionization of 1st atom and 496 kJ/mol is the first ionization of 2nd atom

Explanation:

Given electronic configurations are :

1st: $1s^22s^22p^6$

2nd : $1s^22s^22p^63s^1$

given 1st ionization energy are: 2080 kJ/mol and 496 kJ/mol

generally ionization energy of fulfilled orbital is more than half filled orbital and these two state are more stable.

therefore ionization energy of fulfilled is more than half filled orbital

hence

ionization energy of 1st atom will be very high because its orbital is fulfilled and less energy for 2nd atom so 2080 kJ/mol is the first ionization of 1st atom and 496 kJ/mol is the first ionization of 2nd atom.