Answer:
A. iodine
C. fluorine
F. bromine
Explanation:
Ionic bonds occur mostly between metals and non-metals. Usually, a wide electronegativity difference is preferred between the two atoms. This makes one atom more desirous to gain electron and other more willing to donate electrons.
To have Zn forming a compound in the ratio of 1 to 2, the combining power must be similar to this.
The dominant oxidation state of Zn is the is the +2 state.
The other combining atoms must have the ability to recieve the two electrons.
The halogens fit perfectly into this picture. They need just an electron to attain nobility. They are also highly electronegative. If two halogens combines with the Zn, then the ionic bond will result.
The halogens are fluorine,chlorine, bromine, iodine and astatine.
They will form these compounds:
ZnF₂, ZnBr₂ and ZnI₂
Answer:
Two
Explanation:
The law of conservation of mass states that in an isolated system the mass present is neither destroyed nor created by chemical changes or physical changes.
This tells us that the mass of reactants must be equal to the product mass.
If 1 atom of Zn react with one atoms of sulfur, the product will be 1 molecule of zinc sulfide according to the equation below
Zn(s) + S(s) ⇒ ZnS(s)
therefore two atoms each f zinc and sulfur will product two molecules of Zn sulfide
<span>To draw an acceptable lewis structure we must first determine the number of valance elections of the molecule in the ground state, and then adjust the molecule to refect the molecular radial cation after one or more of the electrons have been removed from its outter most shell. The lewis structure should refect the best configuation with good resonance and stability.</span>
Answer:
It sounds like they are studying French phonemes
Explanations:
I just learned this.
For this problem, we use the formula for sensible heat which is written below:
Q= mCpΔT
where Q is the energy
Cp is the specific heat capacity
ΔT is the temperature difference
Q = (55.5 g)(<span>0.214 cal/g</span>·°C)(48.6°C- 23°C)
<em>Q = 304.05 cal</em>
