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____ [38]
2 years ago
9

How many moles are there in 5.699 liters of neon gas at STP? Express your answer with the appropriate significant figures and un

it.
Chemistry
1 answer:
Svetradugi [14.3K]2 years ago
4 0

Answer:

The number of moles: 0.25442 moles

Explanation:

One mole of Neon gas will occupy 22.4 at STP.

5.699L consists of \frac{5.699}{22.4} = 0.25442 moles.

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In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?
vladimir2022 [97]

Answer:

The volume of the container is 59.112 L

Explanation:

Given that,

Number of moles of Oxygen, n = 3

Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

We need to find the volume of the container. For a gas, we know that,

PV = nRT

V is volume

R is gas constant, R =  0.0821 atm-L/mol-K

So,

V=\dfrac{nRT}{P}\\\\V=\dfrac{3\ mol\times 0.0821\ L-atm/mol-K \times 300\ K}{1.25\ atm}\\\\V=59.112\ L

So, the volume of the container is 59.112 L

6 0
2 years ago
given that the molar mass of Na2SO4 × nH2O is 322.1 g/mol calculate the number of moles of water in this hydrate
Masja [62]
The molar mass of anhydrous Na₂SO₄ = [2(23) + 32 + 4(16)]
                                                                = 142 g/mol

If the molar mass of hydrated Na₂SO₄ = 322 g/mol

Since hydrated salt = Anhydrous Salt + Water

Then the mass of hydration (Water)= 322 g/mol - 142 g/mol    
                                                           = 180 g/mol

Since the molar mass of water itself is 18 g/mol
⇒ Moles of water = 180 g/mol ÷ 18g/mol
                              = 10

Thus n = 10; the formula of the hydrated salt is Na₂SO₄ · 10H₂O (Sodium Sulphate Decahydrate)
7 0
2 years ago
20 point, pls help. A 5.50 mole sample of a gas has a volume of 2.50 L. What would the volume be if the amount increased to 11.0
alexandr1967 [171]

Answer:

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5 0
1 year ago
Describe how to use Le Chatelier’s principle to predict the possible ways a chemical system can respond to changes.
Andre45 [30]
Le Chatelier's principle simply explains how equilibria change as you change the conditions of a reaction. If you have a reaction that is at equilibrium lets say (A + 2B <--> C + D) by removing C or D we can drive the reaction forward and products more products. I can provide a more in-depth description if needed.
4 0
2 years ago
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Which two scenarios illustrate the relationship between pressure and volume as described by Boyle’s law?
Airida [17]

The correct answer is option 2 and 3.

The two scenarios that illustrate the relationship between pressure and volume as described by Boyle’s law are as follows:

2. The volume of an underwater bubble increases as it rises and the pressure decreases.

3. The pressure increases in an inflated plastic bag when the bag is stepped on.

According to Boyle's law, pressure of a gas is inversely proportional to its volume at constant temperature. This means that pressure rises as the volume increases and vice versa.

3 0
2 years ago
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