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Agata [3.3K]
2 years ago
13

You and your lab group have been asked to design an investigation to determine the effects of heat transfer between two differen

t objects.
Which of the following investigation designs explains the heat transfer when atoms directly touch?
А
Boiling water, in a pan, sitting on a lit Bunsen burner.
B
Boiling water, in a pan, in front of a lit Bunsen burner.
С
Hands warming in front of a lit Bunsen burner.
D
Hands touching the handle of pan sitting on a lit Bunsen burner.
Chemistry
1 answer:
GREYUIT [131]2 years ago
5 0
I believe that answer is D
The heat from the Bunsen burner transfers to the water and the pot, then the heat from the pot transfers to the person’s hand.
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Which choice below correctly completes the sentence? _______ reaches the Earth's surface through _______, then turns into ______
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Answer:

d , before the molten rock becomes lava, it is first magma, and most people know that lava is ejected from volcanoes

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You are eating a pizza. What type of mixture are you consuming?
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Answer:

Explanation:

Cheese, Meat, dough, Sauce

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The average density of a carbon-fiber-epoxy composite is 1.615 g/cm3. the density of the epoxy resin is 1.21 g/cm3 and that of t
ra1l [238]
The composite material is composed of carbon fiber and epoxy resins. Now, density is an intensive unit. So, to approach this problem, let's assume there is 1 gram of composite material. Thus, mass carbon + mass epoxy = 1 g.

Volume of composite material = 1 g / 1.615 g/cm³ = 0.619 cm³
Volume of carbon fibers = x g / 1.74 g/cm³ 
Volume of epoxy resin = (1 - x) g / 1.21 g/cm³ 

a.) V of composite = V of carbon fibers + V of epoxy resin
0.619 = x/1.74 + (1-x)/1.21
Solve for x,
x = 0.824 g carbon fibers
1-x = 0.176 g epoxy resins

Vol % of carbon fibers = [(0.824/1.74) ÷ 0.619]*100 =<em> 76.5%</em>

b.) Weight % of epoxy = 0.176 g epoxy/1 g composite * 100 = <em>17.6%</em>
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4 0
2 years ago
A 50.0 mL sample of 0.600 M calcium hydroxide is mixed with 50.0 mL sample of 0.600 M hydrobromic acid in a Styrofoam cup. The t
TEA [102]

Explanation:

The reaction equation will be as follows.

     Ca(OH)_{2}(aq) + 2HBr(aq) \rightarrow CaBr_{2}(aq) + 2H_{2}O(l)

So, according to this equation, 1 mole Ca(OH)_{2} = 2 mol HBr = 1 mol CaBr_{2}

Therefore, calculate the number of moles of calcium hydroxide as follows.

     No. of moles of Ca(OH)_{2} = V \times Molarity

                                    = 50 \times 0.6

                                    = 30 mmol

Similarly, calculate the number of moles of HBr as follows.

        No. of moles of HBr = M \times V

                                          = 50 \times 0.6

                                          = 30 mmol

This means that the limiting reactant is HBr.

So, no. of moles of CaBr_{2} = 30 \times \frac{1}{2}

                                                     = 15 mmol

Hence, calculate the amount of heat released as follows.

                Heat released in the reaction(q) = m \times s \times \Delta T

as,    m = mass of solution

and,             Density = \frac{mass}{volume}

or,                  mass = Density × Volume

                               = 1.08 g/ml \times (50 + 50) ml

                               = 108 g

where,    s = specific heat of solution = 4.18 j/g.k

and,        change in temperature \Delta T = (26 - 23)^{o}C

                                                                 = 3&#10;^{o}C

Hence, the heat released will be as follows.

                   q = m \times s \times \Delta T

                        q = 108 \times 4.18 \times 3^{o}C

                           = 1354.32 joule

or,                        = 1.354 kJ       (as 1 kJ = 1000 J)    

Also,          \Delta H_{rxn} = \frac{-q}{n}

                              = \frac{-1.354}{15 \times 10^{-3}}

                              = -90.267 kJ/mol

Thus, we can conclude that the enthalpy change for the given reaction is -90.267 kJ/mol.

6 0
2 years ago
How many electrons are involved in one equivalent of oxidation-reduction?
kotegsom [21]

Answer:

1 electron is involved.

Explanation:

Hello,

In redox reactions, when therer's the necessity to know the involved equivalents, they equal the number of transferred electrons, in this case, since one equivalent is stated, one electron is transferred (involved).

Best regards.

3 0
2 years ago
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