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Katarina [22]
2 years ago
6

A teacher wants to figure out The amount of a solution that is needed for a titration experiment in a class lab! the class has 1

5 students in each experiment needs 50 mL of solution. if each student will perform the experiment two times how many milliliters of a solution will the teacher need for the whole class
Chemistry
2 answers:
AnnZ [28]2 years ago
5 0
The teacher needs 1500 mL for the whole class.
Anastaziya [24]2 years ago
3 0

<u>Answer:</u> Teacher would require 1500mL of solution for the whole class.

<u>Explanation:</u>

It is given that 50mL of a solution is required by 1 student to perform 1 set of titration and each student does the experiment 2 times, so every student would require (50 × 2) = 100mL of the solution.

There are in total 15 students in the class, so total volume of the solution required by the class will be = ( 15 × 100) = 1500mL

Hence, teacher would require 1500mL of solution for the whole class.

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Given that the rate constant is 4.0×10−4 m−1 s−1 at 25.0 ∘c and that the rate constant is 2.6×10−3 m−1 s−1 at 42.4 ∘c, what is t
stepladder [879]
So here's how you find the answer:

Given: (rate constants)

K₁ = 4.0 x 10⁻⁴ M⁻¹s⁻¹.
T₁ = 25.0 C = 293 K.
k₂ = 2.6 x10⁻³ M⁻¹s⁻¹.
T₂ = 42.4 C = 315.4 K.
R = 8,314 J/K·mol.

Use the equation:

ln(k₁/k₂) = Ea/R (1/T₂ - 1/T₁).

Transpose:

Ea = R·T₁·T₂ / (T₁ - T₂) · ln(k₁/k₂)

Substitute within the given transposed equation:

<span>Ea = 8,314 J/K·mol · 293 K · 315.4 K ÷ (293 K - 315.4 K) · ln (4.0 x 10⁻⁴ M⁻¹s⁻¹/ 2.6 x 10⁻³ M⁻¹s⁻¹).
</span>
Continuing the solution we get:

<span>Ea = 768315 J·K/mol ÷ (-22,4 K) * (-1.87)
</span>
The value of EA is:

<span>Ea = 64140.58 J/mol ÷ 1000 J/kJ = 64.140 kJ/mol.</span>


4 0
2 years ago
Lead is malleable, so it can be pounded into flat sheets without breaking. How does the bonding within lead help to explain this
jarptica [38.1K]

The answer is Metallic bonds involve many valence electrons shared by many atoms, so the bonds can move around as the metal is pounded. The metallic bond structure of lead forms a cubic crystal structure and the atoms can roll over one another without breaking the metallic bonds. This is especially because the p orbital electrons of lead can be delocalized and the electrons can be shared with other lead ions in the cubic structure of lead.

9 0
2 years ago
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In the equilibrium system described by: PO43-(aq) + H2O(1) = HPO42-(aq) + OH-(aq) Brønsted-Lowry theory would designate: A) PO43
Kamila [148]

Answer:

The correct option is:  B) H₂0 and OH⁻ as a conjugate pair

Explanation:

According to Brønsted-Lowry theory, the<u> </u><u>acids</u><u> are the chemical substances that form a conjugate base by donating a proton</u> and <u>bases</u><u> are the chemical substances that form conjugate acid by accepting a proton.</u>

In the given chemical reaction: PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

<u>According to Brønsted-Lowry theory, PO₄³⁻ and OH⁻ are bases. Whereas, H₂O and HPO₄²⁻ are acids.</u>

<u>Also, PO₄³⁻ and HPO₄²⁻ are the conjugate acid-base pair; and H₂O and OH⁻ are the conjugate acid-base pair.</u>

6 0
2 years ago
A piece of unknown metal weighs 500 g. When the piece of metal absorbs 6.64 kJ of heat, its temperature increases from 25°C to 7
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4 0
2 years ago
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Tpy6a [65]

Answer:

Calcium

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Also, since the oxide MO when dissolved in water is basic, the metal is an alkali earth metal.

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The metal is not arsenic because arsenic is a metalloid has the  following oxides As₂O₃ and As₃O₅ and are respectively amphoteric and acidic in nature

The metal is not germanium because is a metalloid and even though germanium oxide has the formula GeO₂, it is amphoteric.

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The metal is not selenium because selenium is anon-meal and its oxide has the formula Se0₂ and is acidic

5 0
2 years ago
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