Answer : The mole fraction of nitrogen will be 0.4615.
Explanation : When nitrogen ()and hydrogen (
)are mixed, the mole ratio becomes 1 : 1.5,
Now we know that () is acting as a limiting agent.
So at the time of when 0.4 moles of () is been formed it requires 0.4 moles of (
) and 3.4 moles of (
)
So, we find the the remaining () will be 0.6 and
() will be 0.3 mole present in mixture.
So, the mole fraction of () becomes = 0.6 / (0.6 + 0.4 + 0.3) Which becomes = 0.4615
The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.
Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).
Nomenclature:
In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.
Name of Formate:
Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.
E.g.
HCOOH (formic acid) → HCOO⁻ (formate) + H⁺
H₃CCOOH (acetic acid) → H₃CCOO⁻ (acetate) + H⁺
Formal Charges:
Formal charges are calculated using following formula,
F.C = [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]
For Oxygen:
F.C = [6] - [6 + 2/2]
F.C = [6] - [6 + 1]
F.C = 6 - 7
F.C = -1
For Sodium:
F.C = [1] - [0 + 0/2]
F.C = [1] - [0]
F.C = 1 - 0
F.C = +1
