<span>Molar mass(C)= 12.0 g/mol
Molar mass (O2)=2*16.0=32.0 g/mol
Molar mass (CO2)=44.0 g/mol
18g C*1mol C/12 g C = 1.5 mol C
C + O2 → CO2
from reaction 1 mol 1 mol 1 mol
from problem 1.5 mol 1.5 mol 1.5 mol
1.5 mol O2*32 g O2/1 mol O2 = 48 g O2
In reality this reaction requires only 48 g O2 for 18 g carbon.
And from 18 g carbon you can get only
1.5 mol CO2*44 g CO2/1 mol CO2=66 g CO2
But these problem has 72g CO2. The best that we can think, it is a mix of CO2 and O2.
So to find all amount of O2 that was added for the reaction (probably people who wrote this problem wanted this)
we need (the mix of 72g - mass of carbon 18 g)= 54 g.
So the only answer that is possible is </span><span>2.) 54 g.</span>
Answer:
3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3
Explanation:
Answer:
37.65mL
Explanation:
Given parameters:
density of liquid Z = 0.9237g/mL
Mass of liquidZ + mass of cup = 50.7g
Mass of cup= 15.92g
Volume of liquid Z in cup=?
Solution:
Density is the mass per unit volume of a substance. It is mathematically expressed as shown below:
Density = 
To find the volume of liquid Z, we know the density of the liquid but we dont know the mass yet.
Mass of liquidZ = 50.7g - mass of cup = 50.7g - 15.92g = 34.98g
Therefore:
Volume of liquidZ = 
=
= 37.65mL
A significant figure is every symbol that made the number itself.
In this case, the number 40.00 has four figures but only two of them are significant 40, this is because you haven't got any more decimals than the first zero.
If you have a case with zeros in front, you take to the first non zero digits.
For example, 0.071004 you wold express as 0.071 and those 7, and 1 are the significant ones.