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melamori03 [73]
2 years ago
8

A scientist adds heat to each of the following substances. Which will probably absorb the most heat before its temperature chang

es significantly?
A. 50 g of solid copper
B. 50 g of solid iron
C. 50 g of liquid water
D. 50 g of sand
Chemistry
2 answers:
sammy [17]2 years ago
6 0
A scientist adds heat to each of the following substances.The one that<span> will probably absorb the most heat before its temperature changes significantly is
</span> 50 g of liquid water
because water has larger heat capacity
so correct option is C
hope it help
anzhelika [568]2 years ago
6 0

Answer: Option (C) is the correct answer.

Explanation:

Specific heat is defined as the amount of heat necessary to raise the temperature of substance by one degree Celsius.  

Mathematically,           Q = mc \Delta t

where      Q = heat

                m = mass of substance

                 c = specific heat

                \Delta t = change in temperature  

Since mass is same for all the given substances. Therefore, more is the specific heat of a substance more frequently it will raise the temperature.

  • Specific heat of copper is 0.385.
  • Specific heat of iron is 0.444.
  • Specific heat of liquid water is 4.184.
  • Specific heat of sand is 0.290.

Thus, we can see that specific heat of liquid water is highest out of the given options.

Hence, we can conclude that liquid water absorb most heat before its temperature changes significantly.

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sergij07 [2.7K]

Answer:

Hydrogen peroxide should be stored in

1) a cool environment

2) with amber bottles away from sunlight

3) with little drops of sodium phosphate

Explanation:

It has been confirmed that heat and light aids in the decomposition of hydrogen peroxide according to the equation; 2H2O2→2 H2O + O2.

This means that hydrogen peroxide must be stored in a cool place. This will reduce its rate of decomposition. Secondly, it should be stored in amber bottles away from light since light also aids in its decomposition.

Thirdly, drops of sodium phosphate may be added to prevent its catalytic decomposition during storage.

8 0
2 years ago
The Mond process produces pure nickel metal via the thermal decomposition of nickel tetracarbonyl: Ni(CO)4 (l) → Ni (s) + 4CO (g
Yuki888 [10]

<u>Answer:</u> The volume of CO formed is 254.43 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of Ni(CO)_4 = 444 g

Molar mass of Ni(CO)_4 = 170.73 g/mol

Putting values in above equation, we get:

\text{Moles of }Ni(CO)_4=\frac{444g}{170.73g/mol}=2.60mol

For the given chemical reaction:

Ni(CO)_4(l)\rightarrow Ni(s)+4CO(g)

By stoichiometry of the reaction:

1 mole of nickel tetracarbonyl produces 4 moles of carbon monoxide.

So, 2.60 moles of nickel tetracarbonyl will produce = \frac{4}{1}\times 2.60=10.4mol of carbon monoxide.

Now, to calculate the volume of the gas, we use ideal gas equation, which is:

PV = nRT

where,

P = Pressure of the gas = 752 torr

V = Volume of the gas = ? L

n = Number of moles of gas = 10.4 mol

R = Gas constant = 62.364\text{ L Torr }mol^{-1}K^{-1}

T = Temperature of the gas = 22^oC=(273+22)K=295K

Putting values in above equation, we get:

752torr\times V=10.4mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 295K\\\\V=254.43L

Hence, the volume of CO formed is 254.43 L.

5 0
2 years ago
The chemical equation, Cr + Fe(NO3)2 → Fe + Cr(NO3)3, is an example of which type of reaction?
Angelina_Jolie [31]

Answer:

Redox type

Explanation:

The reaction is:

2Cr +  3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃

2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.

If we see oxidation state, we see that chromium changes from 0 to +3

Iron changed the oxidation state from +2 to 0

Remember that elements at ground state has 0, as oxidation state.

Iron is being reduced while chromium is oxidized. Then, the half reactions are:

Fe²⁺  +  2e⁻ ⇄  Fe    (Reduction)

Cr ⇄ Cr³⁺  +  3e⁻    (Oxidation)

When an element is being  reduced, while another is being oxidized, we are in prescence of a redox reaction.

8 0
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Consider the following equilibrium system: 3O2(g)  2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone
Rashid [163]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

 <span>3O2(g) <--> 2O3(g); 

Keq = 1 = [O3]^2/[O2]^3 

So [O2]^3 = [O3]^2 

Thus A) is correct</span>
7 0
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Answer:

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Explanation:

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