Explanation:
It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.
or 
So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.
Answer : The concentration of 
in the solution is, 
Explanation :
First we have to calculate the volume of aqueous solution that is water.
Density of water = 1.00 g/mL
Mass of water = 2400 g
Now we have to calculate the concentration of ammonia solution.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Molar mass of = 17 g/mole
Now put all the given values in this formula, we get:
Therefore, the concentration of in the solution is,
Mass of the gas m = 1.66
The calculated temperature T = 273 + 20 = 293
We have to calculate molar mass to determine the gas
Molar Mass = mRT / PV
M = (1.66 x 8.314 x 293) / (101.3 x 1000 x 0.001)
M = 4043.76 / 101.3 = 39.92 g/mol
So this gas has to be Argon Ar based on the molar mass.
C. The salt bridge maintains the flows of ions and allows electrons to move from the anode to the cathode.
So here's how you find the answer:
Given: (rate constants)
K₁ = 4.0 x 10⁻⁴ M⁻¹s⁻¹.
T₁ = 25.0 C = 293 K.
k₂ = 2.6 x10⁻³ M⁻¹s⁻¹.
T₂ = 42.4 C = 315.4 K.
R = 8,314 J/K·mol.
Use the equation:
ln(k₁/k₂) = Ea/R (1/T₂ - 1/T₁).
Transpose:
Ea = R·T₁·T₂ / (T₁ - T₂) · ln(k₁/k₂)
Substitute within the given transposed equation:
<span>Ea = 8,314 J/K·mol · 293 K · 315.4 K ÷ (293 K - 315.4 K) · ln (4.0 x 10⁻⁴ M⁻¹s⁻¹/ 2.6 x 10⁻³ M⁻¹s⁻¹).
</span>
Continuing the solution we get:
<span>Ea = 768315 J·K/mol ÷ (-22,4 K) * (-1.87)
</span>
The value of EA is:
<span>Ea = 64140.58 J/mol ÷ 1000 J/kJ = 64.140 kJ/mol.</span>
