Answer:
A
Explanation:
Iron has the ground state electronic configuration [Ar]3d64s2
Fe2+ has the electronic configuration [Ar]3d6.
In an octahedral crystal field, there are two sets of degenerate orbitals; the lower lying three t2g orbitals, and the higher level two degenerate eg orbitals. Strong field ligands cause high octahedral crystal field splitting, there by separating the two sets of degenerate orbitals by a tremendous amount of energy. This energy is much greater than the pairing energy required to pair the six electrons in three degenerate orbitals. Since CN- is a strong field ligand, it leads to pairing of six electrons in three degenerate orbitals
A) Magnets can attract through solid materials.
The answer to this question would be: <span>thermal metamorphism
</span>
Metamorphism is a change in the mineral texture without causing the rock to become liquid/magma. In this case, the metamorphic change to the rock is caused by the heat energy or thermal energy of the magma. This kind of mechanism is also called contact mechanism as the thermal energy is transferred by contact so this question option is a bit ambiguous.
Answer:
Inventory management documentation
Explanation:
Inventory management documentation is a system of tracking the company's stock. In ordinary terms, Inventory management refers to the sequential processes which include; ordering, storing, and using a company's inventory. The scope of inventory management also covers the management of raw materials, components, and finished products as well as warehousing and processing such items.
Inventory management documentation will surely aid Lin to know what employee has received his/her laptop and who has not from his inventory records. The scope of Inventory management documentation transverses the entire spectrum of a supply chain.
Let us differentiate accuracy from precision. Accuracy is the nearness of the measured value to the true or exact value. On the other hand, precision is the nearness of the measured values between each other. So, for precision, select the student in which the measured values are very near to each other. That would be Student III. Now, for accuracy, let's find the average for each student.
Student I: (<span>8.72g+8.74g+8.70g)/3 = 8.72 g
Student II: (</span><span>8.56g+8.77g+8.83g)/3 = 8.72 g
Student III: (</span><span>8.50g+8.48g+8.51g)/3 = 8.50 g
Student IV: (</span><span>8.41g+8.72g+8.55g)/3 = 8.56 g
From the given results, the accurate one would be Students I and II. So, we make a compromise. Even though Student III is precise, it is not accurate. If you compare between Students I and II, the more precise data would be Student I. Therefore, the answer is Student I.</span>
