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Lera25 [3.4K]
1 year ago
15

A pure gold bar is made of 19.55 mol of gold. What is the mass of the bar in grams

Chemistry
2 answers:
Bogdan [553]1 year ago
8 0
<span>19.55 x 196.97 = 
3850.76 </span>
Law Incorporation [45]1 year ago
4 0
<span>(19.55 mol Au) / ( 1 ) x (196.97 g Au) / ( 1 mol Au) =
19.55 x 196.97 = 
3850.76 g Au

I hope this helps you and have a great day!! :)
</span>
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Answer:

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You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes
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Answer:

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Explanation:

Hello,

In this case, since iron (III) chloride (FeCl3) and barium chloride (BaCl2) are both chloride-containing compounds, we can compute the moles of chloride from each salt, considering the concentration and volume of the given solutions, and using the mole ratio that is 1:3 and 1:2 for the compound to chlorine:

n_{Cl^-}=0.50L*0.250\frac{molFeCl_3}{L}*\frac{3molCl^-}{1molFeCl_3}=0.375molCl^-  \\\\n_{Cl^-}=0.425L*0.350\frac{molBaCl_2}{L}*\frac{2molCl^-}{1molBaCl_2}=0.2975molCl^-

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Finally, the molarity turns out:

M=\frac{0.6725molCl^-}{0.925L}\\ \\M=0.727M

Best regards.

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