Answer:
Explanation:
The given overall reaction is as follows:
O
2
N
N
H
₂(
a
q
)
k
→
N
₂O
(
g
)
+
H
₂
O(
l
)
The reaction mechanism for this reaction is as follows:
O
₂
N
N
H
₂
⇌
k
1
k
−
1 O
₂N
N
H
⁻
+
H
⁺
(
f
a
s
t e
q
u
i
l
i
b
r
i
u
m
)
O
₂
N
N
H
−
k
₂→
N
₂
O
+
O
H
⁻
(
s
l
ow
)
H
⁺
+
O
H
−
k
₃→
H
₂
O
(
f
a
s
t
)
The rate law of the reaction is given as follows:
k
=
[
O
₂
N
N
H
₂
] / [
H
⁺
]
The rate law can be determined by the slow step of the mechanism.
r
a
t
e
=
k
₂
[
O
₂
N
N
H
⁻
]
.
.
.
(
1
)
Since, from the equilibrium reaction
k
e
q
=
[
O
₂
N
N
H
⁻
]
[
H
⁺
]
/[
O
₂
N
N
H
₂
]
=
k
₁
/k
−
1
[
O
₂
N
N
H
⁻]
=
k
₁
/k
−
1 ×
[
O
₂
N
N
H
₂
]
/[
H
⁺
].
.
.
.
(
2
)
Substitituting the value of equation (2) in equation (1) we get.
r
a
t
e
=
k
₂
k
₁/
k
−
1 ×
[
O
₂
N
N
H
₂
]
/[
H
⁺
]
Therefore, the overall rate constant is
k = k₂k₁/k-1
Answer:
a. electrophilic aromatic substitution
b. nucleophilic aromatic substitution
c. nucleophilic aromatic substitution
d. electrophilic aromatic substitution
e. nucleophilic aromatic substitution
f. electrophilic aromatic substitution
Explanation:
Electrophilic aromatic substitution is a type of chemical reaction where a hydrogen atom or a functional group that is attached to the aromatic ring is replaced by an electrophile. Electrophilic aromatic substitutions can be classified into five classes: 1-Halogenation: is the replacement of one or more hydrogen (H) atoms in an organic compound by a halogen such as, for example, bromine (bromination), chlorine (chlorination), etc; 2- Nitration: the replacement of H with a nitrate group (NO2); 3-Sulfonation: the replacement of H with a bisulfite (SO3H); 4-Friedel-CraftsAlkylation: the replacement of H with an alkyl group (R), and 5-Friedel-Crafts Acylation: the replacement of H with an acyl group (RCO). For example, the Benzene undergoes electrophilic substitution to produce a wide range of chemical compounds (chlorobenzene, nitrobenzene, benzene sulfonic acid, etc).
A nucleophilic aromatic substitution is a type of chemical reaction where an electron-rich nucleophile displaces a leaving group (for example, a halide on the aromatic ring). There are six types of nucleophilic substitution mechanisms: 1-the SNAr (addition-elimination) mechanism, whose name is due to the Hughes-Ingold symbol ''SN' and a unimolecular mechanism; 2-the SN1 reaction that produces diazonium salts 3-the benzyne mechanism that produce highly reactive species (including benzyne) derived from the aromatic ring by the replacement of two substituents; 4-the free radical SRN1 mechanism where a substituent on the aromatic ring is displaced by a nucleophile with the formation of intermediary free radical species; 5-the ANRORC (Addition of the Nucleophile, Ring Opening, and Ring Closure) mechanism, involved in reactions of metal amide nucleophiles and substituted pyrimidines; and 6-the Vicarious nucleophilic substitution, where a nucleophile displaces an H atom on the aromatic ring but without leaving groups (such as, for example, halogen substituents).
Answer:
C. pieces of hair found at the crime scene.
Explanation:
using the pieces of hair, you can get the DNA of the person. This will give u a better lead in solving the crime.
Hope it helps u ....
According to the conversation of mass, mass cannot be created or destroyed. This means whatever is done to one side, must be done to the other.
There are 4 Phosphorus atoms on the left, there must be 4 on the right. To do this, you must multiply the P2O3 by 2 to get 4 Phosphorus atoms and 6 Oxygen atoms. Now to balance the Oxygen atoms, you must multiply the oxygen atoms on the left by 3.
1 P4 + 3 O2 —-> 2 P2O3
Lastly, this equation type is synthesis (combination) because two reactants are becoming a single product.
Answer:
Given:
- Initial pressure:
. - Volume was reduced from
to 
. - Temperature was raised from
to 
.
New pressure: approximately 
(
.) (Assuming that the gas is an ideal gas.)
Explanation:
Both the volume and the temperature of this gas has changed. Consider the two changes in two separate steps:
- Reduce the volume of the gas from to . Calculate the new pressure,
. - Raise the temperature of the gas from to . Calculate the final pressure,
.
By Boyle's Law, the pressure of an ideal gas is inversely proportional to the volume of this gas (assuming constant temperature and that no gas particles escaped or was added.)
For this gas, 
while 
.
Let 
denote the pressure of this gas before the volume change (
.) Let denote the pressure of this gas after the volume change (but before changing the temperature.) Apply Boyle's Law to find the ratio between 
and 
:
.
In other words, because the final volume is 
of the initial volume, the final pressure is 
times the initial pressure. Therefore:
.
On the other hand, by Amonton's Law, the pressure of an ideal gas is directly proportional to the temperature (in degrees Kelvins) of this gas (assuming constant volume and that no gas particle escaped or was added.)
Convert the unit of the temperature of this gas to degrees Kelvins:
.
.
Let denote the pressure of this gas before this temperature change (
.) Let denote the pressure of this gas after the temperature change. The volume of this gas is kept constant at 
.
Apply Amonton's Law to find the ratio between and :
.
Calculate , the final pressure of this gas:
.
In other words, the pressure of this gas after the volume and the temperature changes would be approximately .
