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2 years ago

How many milliliters of 0.02 M HCl are needed to react completely with 100 mL of 0.01 M NaOH?

Chemistry

2 answers:

Julli [10]2 years ago

7 0

Answer: Option (D) is the correct answer.

Explanation:

Molarity is number of moles divided by volume of the solution.

Mathematically, Molarity = $\frac{no. of moles}{Volume}$

Also, in the given situation number of moles of both HCl and NaOH are equal. Therefore, volume of HCl will be calculated as follows.

$M_{HCl}V_{HCl}$ = $M_{NaOH}V_{NaOH}$

$0.02 M \times V_{HCl}$ = $0.01 M \times 100 mL$

$V_{HCl}$ = $\frac{0.01 M \times 100mL}{0.02}$

= 50 mL

Thus, we can conclude that volume of HCl is 50 mL.

serious [3.7K]2 years ago

3 0

The reaction of HCl and NaOH is HCl + NaOH = NaCl + H2O. So the mole number of HCl and NaOH is equal. So the volume of HCl =0.01*0.1/0.02=0.05 L =50 ml. So the answer is D).

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We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. 
You were given the liters (.120L)
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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