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REY [17]
1 year ago
14

What amount of SeC16 is needed to produce 4.45 mol of chlorine gas in the

Chemistry
1 answer:
AlladinOne [14]1 year ago
6 0

Answer:

1.48 moles of SeCl6 are needed

Explanation:

Based on the reaction:

SeCl6 + O2 → SeO2 + 3Cl2

<em>1 mole of SeCl6 reacts producing 3 moles of Cl2.</em>

To solve this question we need to use the conversion factor:

1mol SeCl6 = 3mol Cl2

As we want to produce 4.45 moles of Cl2, we need:

4.45 mol Cl2 * (1mol SeCl6 / 3mol Cl2) =

<h3>1.48 moles of SeCl6 are needed</h3>
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In 1-2 sentences, explain why weather can be predicted only as probable, not definite. (2 points) Plaese help me ​
anyanavicka [17]

Weather can be predicted only as probable, not definite because the daily weather conditions depends on winds and storms.

It is common observation that weather forecasts are often given as a probability and never in definite terms.

This is because, the weather condition at anytime depends on the temperature of the earth's atmosphere which causes air masses to move leading to wind.

The temperature of the earth's atmosphere changes frequently hence weather conditions also change frequently.

Learn more: brainly.com/question/21209813

8 0
1 year ago
How many moles are in 1.50 g of ethylamine, ch3ch2nh2?
zavuch27 [327]
Mass =  mass/molar  mass  of   ch3ch2nh2
the   molar  mass  of CH3CH2NH2 =  12  +(1x3)+12+(1 x2)+14+(1x2) =45  g/mol

moles  is therefore  =  1.50g /45g/mol =   0.033 moles
6 0
2 years ago
Read 2 more answers
Methane, CH4, reacts with I2 according to the reaction CH4(g)+I2(g)⇌CH3I(g)+HI(g)
gtnhenbr [62]

Answer:

pCH₄ = 105.1 - 0.42 = 104.68 torr

pI₂ = 7.96 -0.42 = 7.54 torr

pCH₃I = 0.42 torr

pHI = 0.42 torr

Explanation:

Kp is the equilibrium constant for the partial pressure of the gases in the reaction, and it is calculated for a general equation:

aA(g) + bB(g) ⇄ cC(g) + dD(g)

Kp = \frac{(pC)^cx(pD)^d}{(pA)^ax(pB)^b}, where p is the partial pressure in the equilibrium. By the reaction given:

CH₄(g) + I₂(g) ⇄ CH₃I(g) + HI(g)

105.1 torr   7.96 torr  0       0            <em> initial partial pressure</em>

-x                  -x            +x     +x          <em> react</em>

105.1-x       7.96-x      x        x            <em>equilibrium</em>

Then:

Kp = \frac{pCH3IxpHI}{pCH4xpI2} = \frac{x^2}{(105.1-x)(7.96-x)}

2.26x10^{-4} = \frac{x^2}{836.596 - 113.06x -x^2}

x² = 0.1891 - 0.0255x -2.26x10⁻⁴x²

0.9997x² + 0.0255x - 0.1891 = 0

Using Bhaskara's rule:

Δ = (0.0255)² - 4x(0.9997)x(-0.1891)

Δ = 0.7568

x = \frac{-b+/-\sqrt{0.7568} }{2a} = \frac{-0.0255 +/-0.8699}{1.9994}

Using only the positive term, x = 0.42 torr.

So,

pCH₄ = 105.1 - 0.42 = 104.68 torr

pI₂ = 7.96 -0.42 = 7.54 torr

pCH₃I = 0.42 torr

pHI = 0.42 torr

8 0
2 years ago
Read 2 more answers
A kettle of water is at 14.5°C. Its temperature is then raised to 50.0°C by supplying it with 5,680 joules of heat. The specific
Tamiku [17]

Answer:- 38.2 g.

Solution:- The equation used for solving this type of calorimetry problems is:

q=mc\Delta T

where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.

Water temperature is increasing from 14.5 degree C to 50.0 degree C.

\Delta T=50.0-14.5  = 35.5 degree C

q is given as 5680 J and specific heat value is 4.186\frac{J}{g.^0C} .

The equation could be rearranged for m as:

m=\frac{q}{c*\Delta T}

Let's plug in the values in it:

m=\frac{5680}{4.186*35.5}

m = 38.2 g

So, the mass of water in the kettle is 38.2 g.


4 0
2 years ago
Read 2 more answers
Are The Reactions Of Ordinary Molecular Hydrogen Slow Or Rapid ? Why ?
olchik [2.2K]
In nature reactions of ordinary molecular hydrogen are slow since it's  a diatomic molecule whose atoms are held together by very strong covalent bonds.The reaction rate of hydrogen varies depending on temperature and the properties of the reactants, for instance under high temperatures above 500°C hydrogen reacts vigorously and with fluorine it reacts explosively even under low temperatures
4 0
2 years ago
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