Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.
2 answers:
Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation:
The skill that must be know in chemistry is writing the chemical equations, because these equations are the representations of chemical reactions between substances. The chemical equation consists of substances reacting on the left side and the products formed on the right side, with a right arrow inserted to show a chemical reaction taking place. The phases of the substances are included by writing them as subscripts contained in a parenthesis.
For chemical reactions involving ions, the superscripts are used and the number is usually placed before the charge (i.e. 2+, not +2).
For the given chemical reaction, the complete chemical equation including the phases given by:
Sulfur is a chemical element with the symbol S and atomic number 16. It is abundant, multivalent, and nonmetallic. Whereas Hydrogen sulfide
is a colorless chalcogen hydride gas with the characteristic is very poisonous, corrosive, and flammable. Hydrogen
is the most abundant chemical substance in the Universe
- Learn more about the chemical equation brainly.com/question/12271256
- Learn more about Hydrogen sulfide brainly.com/question/12592944
- Learn more about Sulfur brainly.com/question/4288925
Grade: 9
Subject: Chemistry
Chapter: the chemical equation
Keywords: the chemical equation, Introduction to Mastering Chemistry, Chemistry, equation, Hydrogen sulfide
Answer : The complete chemical equation is,
Explanation :
As we know that, in a chemical equation the reacting species present on left side and the product formed present on right side and a right arrow inserted between the reactants and product that show a chemical reaction taking place.
In the chemical reaction, the phases of the substances are also included and subscripts and superscripts are also used for the numbers.
For the given chemical reaction, the balanced chemical equation including the phases, is given by:
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Answer:
The mass of the solute and the volume of the solution.
Explanation:
Hello,
In this case, given the formula of molarity:
In such a way, since the moles could not be directly measured, we must measure the mass of the solute and by using its molar mass, one could compute its moles. Moreover, since the solution is composed by the solvent (typically water) and the solute, we consequently must measure the volume of the solution needed for the preparation of such concentration-known solution. In such a way, we can actually prepare the required solution.
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Answer:
Pi bonds (π bonds) are covalent chemical bonds where two lobes of an orbital involved in the bond overlap with two lobes of the other orbital involved. These orbitals share a nodal plane that passes through the nuclei involved. Are generally weaker than sigma links, because their negatively charged electronic density is further from the positive charge of the atomic nucleus, which requires more energy.
They are frequent components of multiple bonds, as is the molecule indicated in our exercise.
The characteristics that distinguish pi bonds from other kinds of interactions between atomic species are described below, beginning with the fact that this union does not allow the free rotation movement of atoms, such as carbon. For this reason, if there is rotation of the atoms, the bond is broken.
Explanation:
In order to describe the formation of the pi bond, first we must talk about the hybridization process, as this is involved in some important links.
Hybridization is a process where hybrid electronic orbitals are formed; that is, where orbitals of atomic sub-levels s and p can get mixed. This causes the formation of sp, sp2 and sp3 orbitals, which are called hybrids.
In this sense, the formation of pi bonds occurs thanks to the overlapping of a pair of lobes belonging to an atomic orbital over another pair of lobes that are in an orbital that is part of another atom.
This orbital overlap occurs laterally, so the electronic distribution is mostly concentrated above and below the plane formed by the linked atomic nuclei, and causes the pi bonds to be weaker than the sigma bonds.
When talking about the orbital symmetry of this type of junction, it should be mentioned that it is equal to that of the p-type orbitals as long as it is observed through the axis formed by the bond. In addition, these junctions are mostly made up of p orbitals.
Since pi bonds are always accompanied by one or two more links (one sigma or another pi and one sigma), it is relevant to know that the double bond that is formed between two carbon atoms has less bond energy than that corresponding to two Sometimes the sigma link between them.
